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Nitella [24]
3 years ago
7

Explain the formation of planets based on our knowledge of the solar system

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Planets form from particles in a disk of gas and dust, colliding and sticking together as they orbit the star. The planets nearest to the star tend to be rockier because the star's wind blows away their gases and because they are made of heavier materials attracted by the star's gravity.

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3. A 240 mL sample of argon gas at 270 K is cooled until the volume is 180 mL. What is the new temperature?
Alexeev081 [22]

Answer:

202.5 K

Explanation:

5 0
3 years ago
20 POINTS!
11Alexandr11 [23.1K]

Answer:

Explanation:

N₂O₄

Nitrogen tetroxide.

SO₃

Sulfur trioxide

NO

Nitrogen monoxide

NO₂

nitrogen dioxide

As₂O₅

Arsenic pentoxide

PCl₃

Phosphorus trichloride

CCl₄

Carbon tetrachloride or tetrachloromethane

H₂O

Water

SeF₆

Selenium hexafluoride. Six fluorine atoms are attached with selenium atom.

N₂O₄

Dinitrogen tetroxide. It is reddish-brown liquid.

SO₃

Sulfur trioxide

4 0
4 years ago
Work is being done in which of these situations? All motions are at a constant velocity (including velocity = zero).
tigry1 [53]

Answer:

None of the above

Explanation:

Work is defined as the force that moves an object through a particular distance:

    Workdone = force x displacement

At constant velocity, the force on a body is zero because such a body is not accelerating.  

    Force is a product of mass and acceleration. Acceleration occurs only when velocity changes with time. If no change in velocity, acceleration does not occur. Therefore, no force is being applied.

 From all the situations given, the condition is set at constant velocity. At constant velocity, there is no acceleration. This implies that no work is done.

5 0
3 years ago
Read 2 more answers
Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces
Alchen [17]

The question is incomplete, here is the complete question:

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 5.0 L flask with 2.2 atm of ammonia gas and 2.4 atm of oxygen gas at 44.0°C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of nitrogen gas to be 0.99 atm.

Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

<u>Answer:</u> The pressure equilibrium constant for the reaction is 32908.46

<u>Explanation:</u>

We are given

Initial partial pressure of ammonia = 2.2 atm

Initial partial pressure of oxygen gas = 2.4 atm

Equilibrium partial pressure of nitrogen gas = 0.99 atm

The chemical equation for the reaction of ammonia and oxygen gas follows:

                    4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(g)

<u>Initial:</u>               2.2          2.4

<u>At eqllm:</u>        2.2-4x      2.4-3x         2x        6x

Evaluating the value of 'x':  

\Rightarrow 2x=0.99\\\\x=0.495

So, equilibrium partial pressure of ammonia = (2.2 - 4x) = [2.2 - 4(0.495)] = 0.22 atm

Equilibrium partial pressure of oxygen gas = (2.4 - 3x) = [2.4 - 3(0.495)] = 0.915 atm

Equilibrium partial pressure of water vapor = 6x = (6 × 0.495) = 1.98 atm

The expression of K_p for above equation follows:

K_p=\frac{(p_{N_2})^2\times (p_{H_2O})^6}{(p_{NH_3})^4\times (p_{O_2})^3}  

Putting values in above equation, we get:

K_p=\frac{(0.99)^2\times (1.98)^6}{(0.22)^4\times (0.915)^3}\\\\K_p=32908.46

Hence, the pressure equilibrium constant for the reaction is 32908.46

5 0
3 years ago
Which hypothesis led to discovery of the proton?
Daniel [21]
When a neutral hydrogen atom loses an electron, and positively-charged particles should remain. A proton should be 1840 times heavier than an electrons. Cathode rays should be attracted to a positively- charged plate.  
5 0
3 years ago
Read 2 more answers
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