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dlinn [17]
3 years ago
12

Explain how particles transfer with radiation

Chemistry
1 answer:
valina [46]3 years ago
4 0
When energy is transferred to an object, the energy of the particles increases. This means the particles have more kinetic energy and they start to move and vibrate faster. As the particles are moving faster they "bump" into other particles and transfer some of their energy to those neighbouring particles.
You might be interested in
What volume is needed to make a 2.45 M solution of KCl using 0.50 mol of KCl
Ivan

Answer:

Explanation:

91.4

grams

Explanation:

C

=

m

o

l

v

o

l

u

m

e

2.45

M

=

m

o

l

0.5

L

2.45

M

⋅

0.5

L

=

m

o

l

m

o

l

=

1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225

m

o

l

⋅

(

39.1

+

35.5

)

g

m

o

l

1.225

m

o

l

⋅

74.6

g

m

o

l

=

1.225

⋅

74.6

g

=

91.4

g

4 0
3 years ago
Which kind of food contains lots of carbphydrates? chicken, cheese. potatoes, nuts
Evgesh-ka [11]
Cheeze is the most one i hope it helps
8 0
3 years ago
Read 2 more answers
If an atom has 7 protons, 8 neutrons, and 10 electrons, then it has a net charge of . On the other hand, if an atom has 3 proton
zloy xaker [14]

Answer:

Neutrons play no role in the net charge of an atom, so you can ignore them here.

Proton = 7

Electron = 10

Net Charge = 7 - 10

= -3

Again,

Proton = 3

Electron = 2

Net Charge = 3 - 2

= 1

4 0
2 years ago
The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches is OCNCI. The molar mass o
TEA [102]

Answer:

These two are equivalent and valid:

       C_3Cl_3N_3O_3

       Cl_3(CN)_3O_3

Explanation:

The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.

<u />

<u>1. Determine the mass of the empirical formula:</u>

OCNCl:

Atomic masses:

  • O: 15.999g/mol
  • C: 12.011g/mol
  • N: 14.007g/mol
  • Cl: 35.453g/mol

Total mass:

  • 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol

<u />

<u>2. Divide the molar mass by the mass of the empirical formula:</u>

  • 232.41g/mol / 77.470g/mol = 3

<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

       O_3C_3N__3Cl_3

Or:

       C_3Cl_3N_3O_3

You might also write CN as a group:

          Cl_3(CN)_3O_3

8 0
3 years ago
⁉️⁉️ 910 x 0.18945 ⁉️⁉️
Evgen [1.6K]
The answer is 172.39950000000002
8 0
3 years ago
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