So if 11 units on the map is 5m in real life, the scale is 11 units= 5m
But we need 100m.
We would need 20 groups of 5m to get 100m.
So we would need 20 groups of 11 units, which is 220 units.
So, on the scale drawing, the square would need to be 220 units by 220 units.
Answer:
0
Step-by-step explanation:
Since we're multiplying by 0, the entire product becomes 0.
Answer:
E
Step-by-step explanation:
every single graph is asimethrical because they have no trend.
Answer:
![a^{3} \sqrt[]{a}](https://tex.z-dn.net/?f=a%5E%7B3%7D%20%5Csqrt%5B%5D%7Ba%7D)
Step-by-step explanation:
Answer:
x = 28 cm
Step-by-step explanation:
Given:
Area of link shaded regions = 84 cm²
Required:
The value of x (diameter of the semicircle/length of the rectangle)
Solution:
Diameter of the semicircle = 2r = x
Length of rectangle (L) = 2r = x
Radius of semicircle (r) = ½x
Width of rectangle (W) = radius of semicircle = ½x
Use 3.14 as π
Area of the link shaded regions = area of rectangle - area of semicircle
Thus:
Area of the link shaded regions = (L*W) - (½*πr²)
Plug in the values
84 = (x*½x) - (½*3.14*(½x)²)
84 = x²/2 - (1.57*x²/4)
84 = x²(½ - 1.57/4)
84 = x²(0.5 - 0.3925)
84 = x²(0.1075)
Divide both sides by 0.1075
84/0.1075 = x²
781.4 = x²
√781.4 = x
27.9535329 = x
x = 28 cm