Ask question

Ask question

All categories

3 years ago

13

PLS HELP FIRST CORRECT ANSWER GETS BRAINLIEST !! A pile of tailings from a gold dredge is in the shape of a cone. The diameter o

f the base is 34 feet and the height is 16 feet. Approximately, how many cubic feet of gravel is in the pile? Use π = 3.14.
A. 14,527 ft³
B. 285 ft³
C. 4,840 ft³
D. 6,032 ft³

2 answers:

KonstantinChe [14]3 years ago

8 0

Answer:

C

Step-by-step explanation:

use volume of cone:

$v = \frac{1 }{3} \pi {r}^{2} h$

then find r which is half of the diameter so r=17 in this case. then you plug everything into the formula and solve.

andre [41]3 years ago

4 0

Answer:

C: $V=4840 (2 s.f.)$

Step-by-step explanation:

The formula for the volume of a cone is:

$V= \frac{1}{3} \pi r^2h$

Therefore,

$V=\frac{1}{3}\times 3.14\times(\frac{34}{2})^2\times 16\\\\V=4840 (2 s.f.)$

You might be interested in

There is a bag filled with 5 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i

liberstina [14]

The probability is 60% that you will get the same colour twice because one colour has more marbles that the other coloured marble.

5 0

3 years ago

Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x

Cerrena [4.2K]

First, we are going to use the Pythagorean identity: $sin^2(x)+cos^2(x)=1$ to rewrite our expression. Solving for $sin^2(x)$ in our Pythagorean identity we get that $sin^2(x)=1-cos^2(x)$ , so we can rewrite our expression as follows:
$\frac{1}{ \sqrt{1-cos^2(x)} } = \frac{1}{ \sqrt{sin^2(x)} } = \frac{1}{sin(x)}$

Next, we are going to use the trig identity: $csc(x)= \frac{1}{sin(x)}$ to completely simplify our expression:
$\frac{1}{sin(x)} =csc(x)$

We can conclude that $\frac{1}{ \sqrt{1-cos^2(x)} }=csc(x)$

3 0

3 years ago

Emma is going camping. each triangle on her tent is 5 feet tall. the square base 4 feet wide. what is the surface area of her te

Virty [35]

10ft squared

I think because 5 times 4 is 20 so 20 divided by 2 is 10 dividing braces of triangle

4 0

2 years ago

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

Please help. I’ll mark you as brainliest if correct!

beks73 [17]

Answer:

x and y can have many values

Step-by-step explanation:

-24x - 12y = -16

Then: 24x + 12y = 16

We know: 6x + 3y = 4

X and Y can have a lot of valoues.

6x + 3y = 4

3 ( 2x + y) = 4

2x + y= 4/3

2x+y= 1.333...

6 0

2 years ago