Answer:
At the highest point the velocity is zero, the acceleration is directed downward.
Explanation:
This is a free-fall problem, in the case of something being thrown or dropped, the acceleration is equal to -gravity, so -9.80m/s^2. So, the acceleration is never 0 here.
I attached an image from my lecture today, I find it to be helpful. You can see that because of gravity the acceleration is pulled downwards.
At the highest point the velocity is 0, but it's changing direction and that's why there's still an acceleration there.
v₀ = initial speed as tarzan grabs the vine = 5.3 m/s
v = final speed as the tarzan reach the maximum height = 0 m/s
h = maximum height gained by the tarzan
m = mass of tarzan
using conservation of energy
initial kinetic energy = final kinetic energy + potential energy
(0.5) m v²₀ = (0.5) m v² + m g h
(0.5) v²₀ = (0.5) v² + g h
(0.5) (5.3)² = (0.5) (0)² + (9.8) h
h = 1.43 m
Answer:
9:00 AM
Explanation:
I took the test and that was the answer
Fill in the fraction: 3,600/90 = 40; turn it into a unit fraction.
40 mi/min