Answer:
the final kinetic energy is 0.9eV
Explanation:
To find the kinetic energy of the electron just after the collision with hydrogen atoms you take into account that the energy of the electron in the hydrogen atoms are given by the expression:
you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is
![E_{n_2-n_1}=-13.6eV[\frac{1}{n_2^2}-\frac{1}{n_1^2}]\\\\E_{2-1}=-13.6eV[\frac{1}{2^2}-\frac{1}{1}]=-10.2eV](https://tex.z-dn.net/?f=E_%7Bn_2-n_1%7D%3D-13.6eV%5B%5Cfrac%7B1%7D%7Bn_2%5E2%7D-%5Cfrac%7B1%7D%7Bn_1%5E2%7D%5D%5C%5C%5C%5CE_%7B2-1%7D%3D-13.6eV%5B%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B1%7D%5D%3D-10.2eV)
-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is:
Force of gravity =mass*graviational acceleration
gravitational acceleration=g=9.81
mass=Density*Volume=.08*7840
force of gravity= .08*7840*9.81
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The answer is A and B
Explanation: the nucleus was viewed as composed of combinations of protons and electrons, the two elementary particles known at the time, but that model presented several experimental and theoretical contradictions.
AND
Protons and neutrons have approximately the same mass, about 1.67 × 10-24 grams.
Answer:
C) Both 1 and 2
Explanation:
The scan tool may include a bi-directional control that allows the technician to control the output of the alternator for testing purposes.
The Diagnostic Trouble Codes (DTCs), are used by automobile manufacturers to diagnose problems related to the vehicle.
The scan tool can also be used to monitor the output voltage of the vehicle to verify if the correct amount of voltage is supplied by the alternator.
Both Technicians A and B are correct because the steps they both take are necessary for the diagnosis of the vehicle.
