Complete Question
The complete question is shown on the first uploaded image
Answer:
The electric field at that point is
Explanation:
From the question we are told that
The radius of the inner circle is ![r_i = 0.80 \ m](https://tex.z-dn.net/?f=r_i%20%20%3D%20%200.80%20%20%5C%20m)
The radius of the outer circle is ![r_o = 1.20 \ m](https://tex.z-dn.net/?f=r_o%20%20%3D%20%201.20%20%5C%20m)
The charge on the spherical shell
The magnitude of the point charge at the center is ![q_c = + 300 nC = + 300 * 10^{-9} \ C](https://tex.z-dn.net/?f=q_c%20%3D%20%20%2B%20300%20nC%20%20%3D%20%20%2B%20300%20%2A%2010%5E%7B-9%7D%20%5C%20C)
The position we are considering is x = 0.60 m from the center
Generally the electric field at the distance x = 0.60 m from the center is mathematically represented as
![E = \frac{k * q_c }{x^2}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20q_c%20%20%20%7D%7Bx%5E2%7D)
substituting values
![E = \frac{k * q_c }{x^2}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20q_c%20%20%20%7D%7Bx%5E2%7D)
where k is the coulomb constant with value ![k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.](https://tex.z-dn.net/?f=k%20%3D%209%2A10%5E%7B9%7D%20%20%5C%20kg%5Ccdot%20m%5E3%5Ccdot%20s%5E%7B-4%7D%20%5Ccdot%20A%5E%7B-2%7D.)
substituting values
![E = \frac{9*10^9 * 300 *10^{-9}}{0.6^2}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B9%2A10%5E9%20%20%2A%20%20300%20%2A10%5E%7B-9%7D%7D%7B0.6%5E2%7D)
![E = 7500 \ N/C](https://tex.z-dn.net/?f=E%20%3D%207500%20%5C%20N%2FC)
Answer:
The law of inertia
Explanation:
A body at rest will remain at rest, and a body in motion will remain in motion unless it is acted upon by an external force
Your answer is A, Ocean Waves- because A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. Ocean waves do just that :)
Hope this helps!!
Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2
Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:
ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.
w=2*π*f
We know that the turntable is set to 33 1/3 rev/m so
the frequency 33.33/60=0.55 Hz
then w=2*π*0.55=3.45 rad/s
Finally the centripetal acceleration at differents radii results equal:
r= 0.05 m ac=3.45^2*0.05=0.50 m/s^2
r=0.1 ac=3.45^2*0.1=1.20 m/s^2
r=0.14 ac=3.45^2*0.14=1.66 m/s^2
Answer:
Explanation:
For calculating resistance of a conductor , the formula is
R = ρ l / A , ρ is specific resistance , l is length and A is cross sectional area of wire.
For first wire length is l₁ , area is A₁ resistance is R₁, for second resistance is R₂ , length is l₂ and area is A₂
Given , l₁ = 2l₂ , A₁ = 4A₂ , area is proportional to square of thickness.
R₁ / R₂ = I₁A₂ / I₂A₁
= 2l₂ x A₁ / 4 I₂A₁
= 1 / 2
2R₁ = R₂
Power = V² / R
Ratio of power = (V² / R₁) x (R₂ / V²)
= R₂ / R₁
= 2 .