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artcher [175]
3 years ago
11

Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an

y external sources of large gravitational or electric fields, and at rest with respect to each other. Both particles carry electric charges that are identical in magnitude and sign. The gravitational and electric forces between the particles happen to have the same magnitude, so each particle experiences zero net force and the distance between the particles remains constant.
Physics
1 answer:
Igoryamba3 years ago
4 0

Answer:

This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:

a=\frac{F}{m}

Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.

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If you mass 35kg on earth what will your mass be on the moon where gravity is 1/6 that of earths. PLZZZZ HElP NEED ASAP
abruzzese [7]

Answer:

Mass will be same on moon as on Earth but weight will be one-sixth of Earth.

Explanation:

Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.

But, the weight of a body depends on gravity as weight is given as:

\textrm{Weight}=\textrm{mass}\times \textrm{acceleration due to gravity}

Therefore, if g is acceleration due to gravity on Earth, then weight on Earth is, W_{E}=mg

Now, gravity on moon is one-sixth of Earth. So, g_{moon}=\frac{1}{6}g

Therefore, weight of the body on moon is, W_{moon}=mg_{moon}=m\times \frac{1}{6}g=\frac{1}{6}mg=\frac{1}{6}W_{E}

Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.

4 0
3 years ago
Change the following as indicated in the brackets.<br> 8m (km,cm)​
Jet001 [13]

metres to kilometres = 1/1000

8 m ⇒ 0.008 km

metres to centimetres = × 100

8 m ⇒ 800 cm

5 0
3 years ago
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How can I solve this?
inysia [295]
There is no equation here
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3 years ago
Which of the following consists of several billion stars and interstellar matter?
zloy xaker [14]
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One of the world's largest Ferris wheels, the Cosmo Clock 21 with a radius of 50.0 m is located in Yokohama City, Japan. Each of
STatiana [176]

Answer:

a = 0.55 m / s²

Explanation:

The centripetal acceleration is given by the relation

         a = v² / r

angular and linear velocities are related

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we substitute

          a = w² r

In the exercise they indicate the angular velocity w = 1 rev/min, let's reduce to the SI system

          w = 1 rev / min (2pi rad / 1rev) (1min / 60s) = 0.105 rad/ s

let's calculate

          a = 0.105² 50.0

          a = 0.55 m / s²

4 0
3 years ago
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