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artcher [175]
2 years ago
11

Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an

y external sources of large gravitational or electric fields, and at rest with respect to each other. Both particles carry electric charges that are identical in magnitude and sign. The gravitational and electric forces between the particles happen to have the same magnitude, so each particle experiences zero net force and the distance between the particles remains constant.
Physics
1 answer:
Igoryamba2 years ago
4 0

Answer:

This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:

a=\frac{F}{m}

Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.

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Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what
yaroslaw [1]

Answer:

Minimum thickness will be 100 nm

Explanation:

We have given refractive index is n = 1.5

Wavelength of the light incidence \lambda= 600 nm

We have to find the smallest thickness of the film so that there will be minimum light reflect

For minimum thickness of non reflecting film

t=\frac{\lambda }{4n} , here t is thickness, \lambda is wavelength and n is refractive index

Putting all values t=\frac{600}{4\times 1.5}=100nm

So minimum thickness will be 100 nm

8 0
3 years ago
Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
soldi70 [24.7K]
Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}

GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} }  \approx 1.42\cdot 10^{12}m

3 0
3 years ago
Which type of heat transfer takes place in a vacuum? (3 points)
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Radiation is the only transfer in a vacuum
3 0
3 years ago
How is friction reduced between an air hockey puck and the table?
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3 0
3 years ago
You are rolling on a skateboard with a constant velocity of 12 m/s. as you are moving you toss a baseball straight up into the a
ANTONII [103]

Your horizontal motion has no effect on the answers.
Your sister is standing on the sidewalk as you skate by.
At the same exact instant that you toss yours, she tosses
another baseball straight up at 25 m/s, and she gets exactly
the same answers as you get.

The acceleration of gravity is 9.8 m/s² down, so each baseball
loses 9.8 m/s of upward speed each second after you toss them.
They can only continue going up for  (25/9.8) = 2.55 seconds.
At that point, each ball has run out of upward gas, stops, turns
around, and starts falling.  It takes the same 2.55 seconds to
return to the same height from which it was tossed.  So each
ball takes (2 x 2.55) = 5.1 seconds to land back in your hands.

The average speed of each ball on the way up is

                (1/2) (speed at the bottom + speed at the top)

             = (1/2) (25 + 0)  =  12.5 m/s ,

and it spends 2.55 seconds rising.

The distance it covers upward is 

                           (average speed) x (time)

                        =      (12.5 m/s)  x  (2.55 sec)

                        =           31.875 meters .

There it is.  The physics and math are bullet-proof, but
the numbers are whacko.

From a skateboard, you tossed a baseball straight up
at  56 miles per hour ... fast enough for it to reach 105 feet,
possibly the height of a 7-story building, before it falls back !

5 0
3 years ago
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