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miss Akunina [59]

3 years ago

11

A sled with a mass of 25.0 kg rests on a horizontal sheet of essentially frictionless ice. It is attached by a 5.00-m rope to a

post set in the ice. once given a push, the sled revolves uniformly in a circle around the post. If the sled makes five complete revolutions every minute, find the F exerted on it by the rope.

1 answer:

Tpy6a [65]3 years ago

7 0

Answer:

The value is $F = 34.3 \ N$

Explanation:

From the question we are told that

The mass of the shed is $m = 25 \ kg$

The length of the rope is $l = 5.0 \ m$

The angular speed of the shed is $w = 5 rev/minute = \frac{2* \pi * 5}{60 }= 0.524 \ rad/sec$

Generally the force exerted on the shed is mathematically represented as

$F = m * w^2 * l$

=> $F = 25 * 0.524^2 * 5$

=> $F = 34.3 \ N$

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Answer:

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Explanation:

Applying the law of conservation of momentum, we have:

Δ $p_{x = 0}$

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From Equation 1:

$v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

From Equation 2:

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$v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }$

Replacing Equation 3 in Equation 4:

$v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}$

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4 years ago

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6 0

3 years ago

Read 2 more answers