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3 years ago

Under what circumstances will a binary star produce a nova?

1 answer:

5 0

When a star uses up all of it's energy and begins to die, it swells up to become a red giant star. This causes its surface gravity to decrease, thereby allowing some of its mass to escape into space. A binary star is a pair of stars that orbit each other because of their gravitational attraction to each other. When one member of the binary pair uses up all of its energy and begins to die, it loses mass due to the reduction in surface gravity. But instead of escaping into space, this mass is attracted to the companion star because of its gravitational pull. That increases the mass of the companion star. In a process that takes thousands of years, enough matter is transfered that causes the temperature and pressure to increase sufficiently to result in nuclear fusion reactions on the companion star. When these nuclear reactions become extremely violent, the released nuclear energy increases the brightness of this companion star dramatically, thereby creating a nova. Therefore, it is the dying of one of the stars in a binary system along with a sufficient transfer of star mass to sustain nuclear reactions that results in a nova.

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A motorist drives south at 20m/s for 3 min then turns west and travels 25 m

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If the motorist travelled at 20 meters a second for three minutes, 3 minutes is the same as 180 seconds, you multiply 20 times 180, which equals 3600, add 25, and the answer is 3625.

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3 years ago

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In the bedroom of your house you would like to run a 240 W toward, a 30 W alarm clock, a 720 W tanning bed, and four 60 W lights

erica [24]

Answer: current = 10.25A

Explanation:

Toward = 240w

Alarm clock = 30w

Tanning bed = 720w

4 60 watts bulb = 60 * 4 = 240w

Total power = 240 + 30 + 720 + 240 = 1230w

Voltage = 120v

Recall that Power = current * voltage

1230 = current * 120

current = 1230/120 = 10.25A

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3 years ago

An unknown radioactive element decays with a half life of 0.210 days. What is the decay constant, expressed in 1/microseconds, f

sergeinik [125]

The amount of a radioactive element over time can be written as:

$N=N_0e^{-\lambda t}$

So, considering that we know the time of its half life, we know how long it takes to get to half the original amount. This is (usint the amount of days in microseconds):

$0.5=1*e^{-\lambda *0.21*24*3600*10^6}\Rightarrow0.5=e^{-1.8144*10^{10}*\lambda}$ $ln(0.5)=-1.8144*10^{10}*\lambda\Rightarrow\lambda=\frac{ln(0.5)}{-1.8144*10^{10}}=3.82*10^{-11}$

Thus, lambda=3.82*10^(-11)/microseconds

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2 years ago

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and

marin [14]

Electric field strength decreases as the distance from the source increases.

<h3>How the distance from the charge affects the magnitude of the electric field?</h3>

The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.

So we can conclude that Electric field strength decreases as the distance from the source increases.

Learn more about source here: brainly.com/question/25578076

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2 years ago

PLEASE HELP!

luda_lava [24]

Answer:

When a body is placed on a table top, it exerts a force equal to its weight downwards on the table top but does not move or fall. (i) Name the force exerted ...

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