Answer:
A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.
Explanation:
A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.
Some of the names of the basic quantities include:
- Mass, denoted by the symbol 'm', with S.I. unit 'kg'
- Length, denoted by symbol 'l', with S.I. unit 'm'
- Time, denoted by symbol 't', with S.I. unit 's'
- Current, denoted by 'I', with S.I. unit 's' 'A'
- Temperature, denoted by 'T', with S.I. unit 'K'
- Amount of substance, denoted by 'n', with S.I. unit 'mol'
- Luminous Intensity, denoted by 'Iv', with S.I. unit 'cd'
- A basic quantity is chosen arbitrarily.
Answer:
35 m
Explanation:
Given :
The distance of the path from the ground to the tree limb = 50 m
The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees
Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;
We know that ,
= 35
Therefore, the bird perched on the tree limb at a height of 35 m.
The given question is incomplete. The complete question is attached with an image below.
Explanation:
Mass flow rate through region A will be calculated as follows.
Rate = 
= 
= 
= 
Therefore, we can conclude that the mass flow rate through region A is .
Answer:
A 1.5 metres per second squared B 0 C 6 0.5
b) 9m
Explanation:
a= v-a/t
a= acceleration measured in metres per second squared
v= final speed measured in metres per second
u= initial speed measured in metres per second
t= time measured in second
A
a=v-a/t
a= 3-0/2
a= 1.5 metres per second squared
Distance in a velocity time graph = area under
To calculate the distance in the first 4 seconds
You divide the graph into triangles and rectangles
Area A (triangle )= 1/2 × base × height
=1÷2 ×2×3
= 3m
Area B (rectangle)= L×B
=2×3
=6m
Area A + Area B= 3+6
= 9m
