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2 years ago

Based on the tug of war pictured below, what is the net force? –190 n 10 n –10 n 190 n

Physics

1 answer:

kirza4 [7]2 years ago

8 0

The net force in the tug of war which is shown in the picture provided will be 0N.

<h3>What is a Force?</h3>

This is defined as the power exerted on a body and the unit of Force is referred to as Newton.

In the tug of war, the net force is gotten by summing up all the forces.

–190N + 10N –10N + 190N = 0N.

Therefore the net force is 0N.

Read more about Force here brainly.com/question/12970081

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If the bat emits a sound at a frequency of 80.2 kHzkHz and hears it reflected at a frequency of 83.5 kHzkHz while traveling at a

solong [7]

To solve this problem we will apply the concepts related to the Doppler Effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other.

Mathematically it can be described as

$v' = v (\frac{f' ( v - v_{bat}) - f ( v + v_{bat})}{f'(v-v_{bat}) + f ( v + v_{bat})})$

Where,

v = Speed of sound

f' = Reflected frequency

f = Emitted Frequency

$v_{bat}$ = Speed of the object

Assuming that the speed of the medium is the speed of sound of 343m / s, we will then have that:

$v' = 343 (\frac{(83.5) (343 -3.9) - 80.2(343+3.9)}{83.5(343-3.9) + 80.2(343+4.3)})$

$v' = 3.0134m/s$

8 0

3 years ago

a person when asked to speak up,increases her sound level from 30dB to 60dB.The amount of power per unit area increased by? a)30

aivan3 [116]

Answer:

d) 1000 times

Explanation:

As we know that difference of sound level is given as

$L_2 - L_1 = 10 Log \frac{I_2}{I_1}$

so here we need to find the ratio of two intensity

it is given as

$Log\frac{I_2}{I_1} = \frac{(L_2- L_1)}{10}$

$Log\frac{I_2}{I_1} = \frac{60 - 30}{10}$

$Log\frac{I_2}{I_1} = 3$

now we have

$\frac{I_2}{I_1} = 10^3$

so it is

d) 1000 times

4 0

3 years ago

4. Using the bone density of 2.0 kg/m3, calculate the mass of an adult femur bone that has a volume of 0.00027 m3.

kolbaska11 [484]

Answer:

$\boxed{\sf Mass \ of \ an \ adult \ femur \ bone = 0.00054 \ kg}$

Given:

Bone density = 2.0 kg/m³

Volume of bone (V) = 0.00027 m³

To Find:

Mass of an adult femur bone (m).

Explanation:

$\sf \implies Density = \frac{Mass (m)}{Volume (V)} \\ \\ \sf \implies \frac{Mass}{Volume} = Density \\ \\ \sf \implies Mass = Density \times Volume \\ \\ \sf \implies Mass = 2.0 \ kg/ \cancel{m^{3}} \times 0.00027 \ \cancel{m^{3}} \\ \\ \sf \implies Mass = 0.00054 \ kg$

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3 years ago

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Nonamiya [84]

It’s could be O SCI2

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2 years ago

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motikmotik

The answer to this question is 1cm/s

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