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Sav [38]
2 years ago
5

Based on the tug of war pictured below, what is the net force? –190 n 10 n –10 n 190 n

Physics
1 answer:
kirza4 [7]2 years ago
8 0

The net force in the tug of war which is shown in the picture provided will be 0N.

<h3>What is a Force?</h3>

This is defined as the power exerted on a body and the unit of Force is referred to as Newton.

In the tug of war, the net force is gotten by summing up all the forces.

–190N + 10N –10N + 190N = 0N.

Therefore the net force is 0N.

Read more about Force here brainly.com/question/12970081

#SPJ4

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What is a temperature where the vapor pressure of a liquid equals the atmospheric pressure.
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A tsunami covers a distance of 500km in 83.3 minutes. If the period of vibration of the molecules is 35.0 minutes, what is the w
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Explanation:

pls give brainliest :)

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3 years ago
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
Consider two metallic rods mounted on insulated supports. One is neutral, the other positively charged. You bring the two rods c
EastWind [94]

Answer:

I think it will be half of the initial charge

Explanation:

Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2

3 0
3 years ago
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