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3 years ago

The bases of the trapezoid are 6 and 10. The heights is 4

Mathematics

1 answer:

dlinn [17]3 years ago

8 0

Answer:

A=32

Step-by-step explanation:

Area of a trapezium=1/2(a+b)h

A=1/2(6+10)4

A=1/2(16)4

divide 16 by 2

A=(8)4

open the bracket

A=32

Check/ verify

A=1/2(a+b)h

32=1/2(6+10)4

32=1/2(16)4

divide 16 by 2

32=(8)4

32=32.

I hope this hopes?

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Someone help me please, this topic is based on slopes.

Paul [167]

Answer:

run / rise =5/1

Step-by-step explanation:

The run is 5 and the rise is 1

3 0

3 years ago

A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An

Gnom [1K]

I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
$tan A = \frac{h+70}{40} , tan B = \frac{70}{40}$

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
$tan (A-B) = \frac{tanA - tanB}{1+tan A tan B}$
Plug in what we know:
$tan(9) = \frac{ \frac{h+70}{40} - \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}$
$tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}$
$h = \frac{650 tan(9)}{4-7 tan(9)}$
$h = 35.6$

7 0

3 years ago

There are 20 packages of beef in a restaurant freezer. The average weight of 14 of the packages is 2 lb. The remaining packages

Shtirlitz [24]

I belive that the answer is about 180 lb.

3 0

2 years ago

Read 2 more answers

How to divide 400 by 40

ipn [44]

Answer:

Step-by-step explanation:

because 40 can go into 400 ten times

also if you do it on long division you will do 10 times 40 is 400

7 0

2 years ago

10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend

ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

=18 +16+14+12+10+8+6+4+2

= 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

=6 +4

=10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

=6 +4

=10

Hence proved.

3 0

3 years ago