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olga_2 [115]
3 years ago
10

A family has an annual income of ​$25,200. Of​ this, 1/4 is spent for​ food, 1/5 or​ housing, 1/10 for​ clothing, one ninth for​

savings, 1/10 for​ taxes, and the rest for other expenses. How much is spent for​ housing?
Mathematics
2 answers:
natita [175]3 years ago
7 0

One fifth of the family's income is spent on housing:

(1/5)($25,200) = $5,040.

STatiana [176]3 years ago
6 0
Simply divide $25,200 by 5
25200 \div 5 = 5040

$5,400 was spent on housing
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beks73 [17]

There are two cases to consider.

A) The removed square is in an odd-numbered column (and row). In this case, the board is divided by that column and row into parts with an even number of columns, which can always be tiled by dominos, and the column the square is in, which has an even number of remaining squares that can also be tiled by dominos.

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Perhaps the shorter answer is that in an odd-sized board, the corner squares are the ones that there is one of in excess. Cutting out one that is of that color leaves an even number of squares, and equal numbers of each color. Such a board seems like it <em>ought</em> to be able to be tiled by dominos, but the above shows there is actually an algorithm for doing so.

7 0
3 years ago
Carl collects coins compulsively, but he only likes quarters ($0.25) and dimes ($0.10). Carl currently has 125 coins for a total
Bogdan [553]

Answer:

Carl has 35 dimes and 90 quarters

Step-by-step explanation:

Let the number of quarters be q and the number of dimes be d

Total number of coins is 125;

Hence;

q + d = 125 •••••••••(i)

The total value of quarters present = q * 0.25 = 0.25q

The total value of dimes present = d * 0.1 = 0.1d

Adding both gives the total

0.25q + 0.1d =26 ••••••••(ii)

So we need to solve both equations simultaneously;

From i,

q = 125 - d

Substitute this into ii

0.25(125-d) + 0.1d = 26

31.25 -0.25d + 0.1d = 26

31.25 -26 = 0.25d -0.1d

5.25 = 0.15d

d = 5.25/0.15

d = 35

Recall; q = 125 - d = 125 -35 = 90

7 0
3 years ago
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Hello,

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3 years ago
This is due today and it would be awesome if someone could do one of these problems so I can see how to do them thanks :)
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