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ohaa [14]
4 years ago
15

Mr. Smith challenged his students to create an electromagnet that will pick up more paper clips than anyone else in the class. T

immy is very excited and begins to collect all of the necessary materials. He finds a D-cell battery, an iron nail, and a large roll of copper wire. What could Timmy do, using just these materials, to increase the strength of his electromagnet to pick up the maximum amount of paper clips?
Physics
1 answer:
Yuliya22 [10]4 years ago
6 0
<h2>Answer:</h2>

Timmy can make the electromagnet strong by the following ways

  • Using a battery having more voltage and current
  • By increasing the number of loops
<h2>Explanation:</h2>

An electromagnet can be made by having a source of voltage that is a battery or a cell, a conductor, and metal piece. Wrap insulated copper wire tightly around an iron screw or nail before connecting the wire to a battery.  Making sure to leave enough of the wire unwound so that it can be attached to the battery. The more wire is wrapped around the nail, the stronger the electromagnet will be. We can make the flux or strength stronger by increasing the voltage and number of loops of wire.

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The length of the new runway In terms of (L) is 4L.

<em />

<em>Your question is incomplete, it seems your question is missing the following information below;</em>

"In terms of (L) , what must be the length of the new runway?"

The given parameters;

  • length of the runway, = L
  • let the take off speed = V₁

For the newly designed planes;

the take off speed is double of the original = 2V₁

the acceleration for both take is constant = a

The take off speed for the given constant acceleration is given as;

v^2 = u^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\a = \frac{v^2}{2s} \\\\

The length of the new runway In terms of (L) is calculated as follows;

a =  \frac{v_1^2}{2s_1}  = \frac{v_2^2}{2s_2}  \\\\substitute \ the \ corresponding \ values \ for \ initial \ acceleration \ and \ new \\acceleration\\\\\frac{v_1^2}{2L}  = \frac{(2v_1)^2}{2s_2}\\\\2s_2v_1^2 = 2L(4v_1^2)\\\\s_2 = \frac{2L(4v_1^2)}{2v_1^2} = \frac{8Lv_1^2}{2v_1^2} = 4L

Thus, the length of the new runway In terms of (L) is 4L.

Learn more here: brainly.com/question/15206976

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3 years ago
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3 0
4 years ago
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Explanation:

From the question we are told that

   The mass of the  Ping-Pong is  m  =  2.3 \  g = 0.0023 \  kg

    The terminal  speed is  v  =  9.3 \  m/s

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Generally the resultant force on the Ping- Pong is mathematically represented as

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=>   b  =  \frac{m *  g}{v^2}

=>    b  =  \frac{0.0023 *  9.8}{ 9.3 ^2}

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