Answer:
The period of rotation is
T=8.025s
Explanation:
The person is undergoing simple harmonic motion on the wheel
Given data
mass of the person =75kg
Radius of wheel r=16m
Velocity =8.25m/s
The oscillating period of simple harmonic motion is given as
T=(2*pi)/2=2*pi √r/g
Assuming that g=9.81m/s
Substituting our data into the expression we have
T=2*3.142 √ 16/9.81
T=6.284*1.277
T=8.025s
Answer:
50 W
Explanation:
<h3>
<u>Given :</u></h3>
- Force applied = 100 N
- Distance covered = 5 metres
- Time = 10 seconds
<h3>
<u>To find :</u></h3>
Power
<h3>
<u>Solution :</u></h3>
For calculating power, we first need to know about the work done.
![\bf \boxed{Work = Force \times displacement}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cboxed%7BWork%20%3D%20Force%20%5Ctimes%20displacement%7D%20)
Now, substituting values in the above formula;
Work = 100 × 5
= 500 Nm or 500 J
We know that,
![\bf \boxed{Power=\dfrac{Work\:done}{Time\: taken}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7BPower%3D%5Cdfrac%7BWork%5C%3Adone%7D%7BTime%5C%3A%20taken%7D%7D)
Substituting values in above formula;
Power = 500/ 10
= 50 Nm/s or 50 W
Hence, power = 50 W .
Answer:
I would believe that it would be the last option
Explanation:
Physical science is a type of science that mainly focuses on natural objects that are not alive, such as minerals and rocks.
Answer:
Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.
Answer:
Object 3 has greatest acceleration.
Explanation:
Objects Mass Force
1 10 kg 4 N
2 100 grams 20 N
3 10 grams 4 N
4 1 kg 20 N
Acceleration of object 1,
![a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{4}{10}\\\\a_1=0.4\ m/s^2](https://tex.z-dn.net/?f=a_1%3D%5Cdfrac%7BF_1%7D%7Bm_1%7D%5C%5C%5C%5Ca_1%3D%5Cdfrac%7B4%7D%7B10%7D%5C%5C%5C%5Ca_1%3D0.4%5C%20m%2Fs%5E2)
Acceleration of object 2,
![a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{20}{0.1}\\\\a_2=200\ m/s^2](https://tex.z-dn.net/?f=a_2%3D%5Cdfrac%7BF_2%7D%7Bm_2%7D%5C%5C%5C%5Ca_2%3D%5Cdfrac%7B20%7D%7B0.1%7D%5C%5C%5C%5Ca_2%3D200%5C%20m%2Fs%5E2)
Acceleration of object 3,
![a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{4}{0.01}\\\\a_3=400\ m/s^2](https://tex.z-dn.net/?f=a_3%3D%5Cdfrac%7BF_3%7D%7Bm_3%7D%5C%5C%5C%5Ca_3%3D%5Cdfrac%7B4%7D%7B0.01%7D%5C%5C%5C%5Ca_3%3D400%5C%20m%2Fs%5E2)
Acceleration of object 4,
![a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{20}{1}\\\\a_3=20\ m/s^2](https://tex.z-dn.net/?f=a_4%3D%5Cdfrac%7BF_4%7D%7Bm_4%7D%5C%5C%5C%5Ca_4%3D%5Cdfrac%7B20%7D%7B1%7D%5C%5C%5C%5Ca_3%3D20%5C%20m%2Fs%5E2)
It is clear that the acceleration of object 3 is
and it is greatest of all. So, the correct option is (3).