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Sunny_sXe [5.5K]
3 years ago
13

The cheetah is one of the fastest accelerating animals, for it can go from rest to 34.5 m/s in 3.57 s. If its mass is 112 kg, de

termine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.
Physics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer: a) 18670 W b) 25 hp

Explanation:

a)

Average power,

P = W/t

W= 0.5 MVf^2 - 0.5 MVo^2

Therefore P =( (0.5 x 112 x 34.5^2 ) - (0.5 x 112 x 0 ) ) / 3.57

P = 1.87 x 10^4 W

b)

Power in units of horsepower is

P = 1.87 x 10^4 / 745.7 = 25hp

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Answer:

The ratio is  KE : TM  =  0.75

Explanation:

from the question we are told that

  The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical  energy of the mass is mathematically represented as

        TM  =  \frac{1}{2}  *  k  *  A^2

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Generally this total mechanical energy is mathematically represented as

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Here the potential  energy of the mass is mathematically represented as

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Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is  

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So

     PE   = \frac{1}{ 2}  *  k *  [ \frac{A}{2}  ]^2

So

      KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{2}  *  k  *  [\frac{A}{2} ]^2

=>    KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{8}  *  k  *  A ^2

=>    KE =  0.375  *  k  *  A^2

So the ratio of  KE :  TM is  mathematically represented as

       \frac{KE}{TM} =  \frac{0.375  k A^2 }{0.5 k A^2}

=>    \frac{KE}{TM} = 0.75

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