Answer:
(A) Q = 321.1C (B) I = 42.8A
Explanation:
(a)Given I = 55A−(0.65A/s2)t²
I = dQ/dt
dQ = I×dt
To get an expression for Q we integrate with respect to t.
So Q = ∫I×dt =∫[55−(0.65)t²]dt
Q = [55t – 0.65/3×t³]
Q between t=0 and t= 7.5s
Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]
Q = 321.1C
(b) For a constant current I in the same time interval
I = Q/t = 321.1/7.5 = 42.8A.
Responda:
400 g
Explicação:
Dado o seguinte:
Deixe Mass (m1) = m em t1 = 45 ° C
Massa (m2) = 200g em t2 = 15 ° C
Equilíbrio térmico (T) = 35 ° C
Usando a relação:
m1 * C * ΔT = m2 * C * ΔT
Onde m1 e m2 são as massas; C = capacidade de calor específico da água e ΔT é a mudança de temperatura
m1 * ΔT = m2 * ΔT
m * (45 ° C - 35 ° C) = 200 * (35 ° C - 15 ° C)
10 * m = 200 * 20
10 * m = 4000
m = 4000/10
m = 400g
The answer is 86 degrees Fahrenheit. Formula is (30 x 9.5) + 32 = 86
Answer:
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Back-end Environmental Impact. ...
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High Up-Front and End Stage Cost.