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Viefleur [7K]
3 years ago
14

The coffee jug hold four times as much as the milk jug everyone has the same sized cup but each person likes different amounts o

f milk in thier coffee jane likes half milk and half coffee jean june joan each like one quarter milk and ian drinks black coffee they fill up thier five cups the way the each like it and just empty one of the jugs how much liquid is left in the other
Mathematics
1 answer:
svetlana [45]3 years ago
7 0
We will assume that each of their cups holds exactly 1 cup of liquid.  Let <em>m</em> represent milk and <em>c</em> represent coffee.
Jane = 1/2<em>m</em> + 1/2<em>c</em> to represent 1/2 milk and 1/2 coffee
Jean, June, and Joan = 3(1/4<em>m</em> + 3/4<em>c</em>) [they all 3 like the same ratio, so multiply the expression by 3], to represent 1/4 milk and 3/4 coffee
Ian = 1<em>c </em>(since he likes black coffee, his entire 1-cup dish of coffee will be coffee)
Adding these together we have:
1/2<em>m</em> + 1/2<em>c</em> + 3(1/4<em>m</em> + 3/4<em>c</em>) + 1<em>c</em>
= 1/2<em>m</em> + 1/2<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Find a common denominator:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Convert the 1 whole to a fraction:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em /><em>m</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>m</em>'s:
= 5/4<em>m</em> + 2/4<em>c</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>c</em>'s:
= 5/4<em>m</em> + 15/4<em>c</em>
We know there is 4 times as much coffee as milk.  Looking at the two fractions we have left, we can see that 15/4<em /> = 3(5/4).  We would expect to see 4(5/4), since there is 4 times as much coffee.  That means we have 5/4 or 1 1/4 of the liquid left.
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<h3>What is scalar multiplication?</h3>
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In this problem, the vector is:

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To learn more about scalar multiplication, you can take a look at brainly.com/question/1821869

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Step-by-step explanation:

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I am not sure what your teacher wants to see on the right side of the second equation.

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Ahora, nos dice que invirtamos los números a1 y c1, por lo tanto, nuestro nuevo número de tres cifras sería:

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