Answer:
The reach of the tongue is 23 cm.
Explanation:
Hi there!
The equation of traveled distance is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = traveled distance at time t.
x0 = initial position.
v0 = initial velocity.
a = acceleration.
t = time.
Let´s calculate the distance traveled by the tongue of the chameleon during the first 20 ms (0.020 s):
The initial position and velocity are zero (x0 = 0 and v0 = 0)
x = 1/2 · a · t²
x = 1/2 · 280 m/s² · (0.020 s)²
x = 0.056 m
Now, let´s find the distance traveled while the tongue moves at constant speed. But first, let´s find the velocity (v) of the tongue after the accelertation interval using the following equation:
v = v0 + a · t (v0 = 0)
v = 280 m/s² · 0.020 s
v = 5.6 m/s
Then, the distance traveled at constant speed can be calculated:
x = v · t
x = 5.6 m/s · 0.030 s
x = 0.17 m
The reach of the tongue is 0.17 m + 0.056 m = 0.23 m = 23 cm.
Answer:
The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x N
The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward
Explanation:
given information:
current, I = 3 A
= +6.5 x C
r = 0.05 m
v = 280 m/s
and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:
F = qvB sin θ
where
F = magnetic force (N)
q = electric charge (C)
v = velocity (m/s)
θ = the angle between the velocity and magnetic field
to find B we use
B = μI/2πr
μ = 4π x or 1.26 x N/ , thus
B = 4π x x 3 / 2π(0.05)
= 1.2 x T
Now, we can calculate the magnitude force
F = qvB sin θ
θ = 90°, because the speed and magnetic are perpendicular
F = 6.5 x x 280 x 1.2 x sin 90°
= 2.18 x N
Using the hand law, the magnetic direction is radially inward
Deacreasing the mass of one objects.
Increasing the mass of one of the objects.
Deacreasing the distance between the objects. (hope this helps)
Given the measured value of mass M in the experiment the error in 2M is ; dM
<u>Given data :</u>
Measured value of mass M = ( 0.743 ± 0.005 ) kg
<h3>The error in 2M in the measured value </h3>
The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
Learn more about error in 2M : brainly.com/question/6650225
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert<span> small force on the wall The </span>pressure exerted<span> by the </span>gas<span> is due to the sum of all these collision forces.The more particles that hit the walls, the higher the </span>pressure<span>.</span>