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2 years ago

When you heat ice on a hot stove, the ice melts. what is happening during this process?

Physics

2 answers:

krek1111 [17]2 years ago

6 0

B. Heat energy is being transferred from the stove to the ice.

masya89 [10]2 years ago

5 0

Heat energy is being transferred

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It requires 49 J of work to stretch an ideal very light spring from a length of 1.4 m to a length of 2.9 m. What is the value of

nadya68 [22]

Answer:

44 N/m

Explanation:

The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m

The work needed to stretch a spring by <em>e</em> is given by

$W = \frac{1}{2} ke^2$

where <em>k</em> is spring constant.

$k = \dfrac{2W}{e^2}$

Using the appropriate values,

$k = \dfrac{2\times 49\text{ J}}{1.5^2\text{ m}^2} = 43.55\ldots\text{ N/m} \approx 44\text{ N/m}$

3 0

3 years ago

Read 2 more answers

A flat metal washer (a circular plate with a circular hole cut out of it) is heated. Does the hole get smaller, larger, or remai

Pepsi [2]

It gets larger since the heat is expanding it outward

6 0

3 years ago

The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it

Lilit [14]

Answer:

(a) Power= 207.97 kW

(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, $m=0.02 kg$

Kinetic energy imparted, $K=1200 J$

Length of rifle barrel, $d=1 m$

(a)

Let the speed of bullet when it leaves the barrel is $v$ .

Kinetic energy, $K=\frac{1}{2} mv^{2}$

$v=\sqrt{\frac{2K}{m} }$

$=\sqrt{\frac{2\times1200}{0.02} }$

$=346.4m/s$

Initial speed of bullet, $u=0$

The average speed in the barrel, $v_a_v_g=\frac{u+v}{2}$

$=\frac{0+346.4}{2} \\=173.2 m/s$

Time taken by bullet to cross the barrel, $t=\frac{d}{v}$

$=\frac{1}{173.2}\\ =0.00577 second$

Power, $P_a_v_g=\frac{W}{t}$

$=\frac{1200}{0.00577} \\=207.97kW$

(b)

In projectile motion,

Maximum height, $H_m=\frac{v^2\sin^2\theta}{2g} \\$

Range, $R=\frac{v^2\sin2\theta}{g}$

given that, $H_m=R$

then, $\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter$

5 0

2 years ago

There is an analogy between rotational and linear physical quantities. what rotational quantities are analogous to distance and

SVEN [57.7K]

ANSWER:

Angular displacement is analogous to distance.

Angular velocity is analogous to velocity.

EXPLANATION:

FOR ANGULAR DISPLACEMENT AND DISTANCE

Angular displacement = theta

theta = s/r

s = linear dispalcement/distance

r= radius.

so ,

linear displacement/distance s = theta * r.

FOR ANGULAR VELOCITY AND VELOCITY

Angular velocity = w

w = v/r

v = velocity

r = radius

so,

velocity v = w * r.

5 0

3 years ago

Read 2 more answers

If a cable insulation is described as RHW, you would be able to use the cable for what maximum temperature?

BartSMP [9]

167•F which is c

Tell me my wrong from right

7 0

3 years ago