Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
Distance travelled S = ut + (at^2)/2
Substituting the values in the second equation of motion,
S = 50*2 + (10 * 2 *2)/2
S = 100 + 20
S = 120 miles
Therefore the distance travelled by the car in the next two hours is 120 miles
Answer:
Explanation:
We have here values from SI and English Units. I will convert the units to English Units.
We hace for the power P,


we have other values such
and
(specific weight of the water), and 0.85 for \eta
We need to figure the flow rate of the water (V) out, that is,

Where
is the turbine efficiency, at which is,

Replacing,


With this value (the target of this question) we can also calculate the mass flow rate of the waters,
through the density and the flow rate,

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

Answer:
12 m/s
Explanation:
divide distance over time
72/6 = 12
Magnitude of change is 15km/h
change in direction is to the right?
Answer:
Explanation:
From the given information:
radius = 15 m
Time T = 23 s
a) Speed (v) = 

v = 4.10 m/s
b) The magnitude of the acceleration is:

a = 1.12 m/s²
c) True weight = mg
Apparent weight = normal force
From the top;
the normal force = upward direction,
weight is downward as well as the acceleration.
true weight - normal force = ma
apparent weight =mg - ma


= 0.886 m/s²
d)
From the bottom;
acceleration is upward, so:
apparent weight - true weight = ma
apparent weight = true weight + ma



= 1.114 m/s²