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Verdich [7]
3 years ago
9

A 225-kg bumper car (and its occupant) is moving north at 98 cm/s when it hits a 198-kg car (occupant mass included) moving nort

h at 28 cm/s. the 198-kg car is moving north at 71 cm/s after the head-on collision. determine the post-collision velocity of the 225-kg car. answer

Physics
1 answer:
stira [4]3 years ago
5 0
To solve the problem you must first know that by keeping the linear moment P1 = P2. You must find P1 from the system and equal it to P2 of the system, from that equation you clear the final velocity 1. Which will result in V1f = 60.16 cm / s to the north.I attach the solution.

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A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
Margaret [11]

Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

           P V = nR T

In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

For pressure the open end of the tube is

         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
3 years ago
Type of force that holds the nucleus of an atom together
Kamila [148]

Answer:

Nuclear Forces

Explanation:

The type  of force that holds the nucleus of an atom together is called Nuclear Forces.

7 0
3 years ago
Write any two features of capital​
amid [387]
Washington DC and new Mexico
6 0
3 years ago
Read 2 more answers
Consider a block of mass m attached to two springs, one on the left with spring constant k1 and one on the right with spring con
Andrew [12]

Answer:

T= 2\pi\times sqrt(m/(k1+k2))

Explanation:

When the block is displaced by x units

F= spring force

two springs are connected parallel

F =-k_1x - k_2x

Writing Newtons second law, F = ma

-k_1x - k_2x =ma

-k_1x - k_2x = mx''

a= x" ( differentiating x w.r.t time twice)

x''+(k_1/m + k_2/m) x=0

this the standard form of equation of oscillation spring mass system

This is the differential equation, x'' means that double differentiation of x , i.e, x'' is acceleration

since,  Period T=2\pi\sqrt{\frac{m}{K_{eq.}} }

therefore,

T= 2\pi\times sqrt(m/(k1+k2))

3 0
3 years ago
If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d = A + Bt^2, the SI units of
Yuliya22 [10]

Answer:

The SI units of the “A” is m (meters)

The SI units of the “B” is m/s^2

Explanation:

Given the distance = d meters.

Time taken to travel = t (seconds)

Function of the distance, d = A + Bt^2

Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.

Thus, the SI units of the “A” is = m (meters)

The SI units of the “B” is = m/s^2

6 0
3 years ago
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