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3 years ago

Which of the following terms describes one’s ability to understand how another person is feeling?

Physics

1 answer:

liq [111]3 years ago

8 0

Answer:

Empathy

Explanation:

Empathy: to understand the thoughts, feelings, or emotional state of another person

Appreciation: to show gratitude

Cooperation: is the association for mutual benefit

Commitment: is the agreement to do something.

From the definitions above, empathy is the term that describes one’s ability to understand how another person is feeling.

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IF U ANSWER I WILL MARK U BRAINLLIEST

goldfiish [28.3K]

Explanation:

a) Density is the amount of mass in a specific amount of volume

b) Some substances are less dense than water so will float and vice versa

c) The wooden plank has less density than water due to having larger volume and vice versa with the wooden block since volume and density are inversely proportional

II) (a) They are all metals

(b) water -> Compound

oxygen -> Element

Gold-> Element

Salt-> Compound

6 0

3 years ago

Read 2 more answers

Suppose the price elasticity of supply for gasoline in the short run is estimated to be 0.4. Due to an unexpected surge in the d

netineya [11]

Answer:

increase by 8 percent

Explanation:

Price elasticity of supply of a product is the degree of responsiveness of supply of that product to a change in price. Simply put:

Price Elasticity of supply = change in quantity supply/ change in price.

In this case, price elasticity of supply of gasoline = 0.4

Percentage price increase = 20 percent.

Hence,

0.4 = change in supply/20

Change in supply = 20 x 0.4 = 8 percent

Therefore, the quantity supply of gasoline will increase by 8 percent

5 0

3 years ago

Finish the sentence

Scrat [10]

The first blank is character
The last one is eye colour.

8 0

3 years ago

Coulomb's law is similar to newton's law of gravitation in several ways. which one of the statements is not a similarity between

PIT_PIT [208]

The only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both forces.

In these contexts, it is considered that repulsive forces are positive and attractive forces are negative. So, Newton's law of gravitation considers gravitational force which only attracts. So, Newton's law of gravitation takes only negative force into account while Coulomb's law considers both electric charges.

According to Newton's law of gravitation,

F = G $m_{1} m_{2}$ / $r^{2}$

According to Coulomb's law

F = k $q_{1} q_{2}$ / $r^{2}$

Therefore, the only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both positive and negative forces.

To learn more about Coulomb's law

brainly.com/question/506926

#SPJ4

4 0

1 year ago

When the magnetic flux through a single loop of wire increases by , an average current of 40 A is induced in the wire. Assuming

Zielflug [23.3K]

COMPLETE QUESTION:

When the magnetic flux through a single loop of wire increases by 30 Tm^2 , an average current of 40 A is induced in the wire. Assuming that the wire has a resistance of 2.5 ohms , (a) over what period of time did the flux increase? (b) If the current had been only 20 A, how long would the flux increase have taken?

Answer:

(a). The time period is 0.3s.

(b). The time period is 0.6s.

Explanation:

Faraday's law says that for one loop of wire the emf $\varepsilon$ is

$(1). \: \: \varepsilon = \dfrac{\Delta \Phi_B}{\Delta t }$

and since from Ohm's law

$\varepsilon = IR$ ,

then equation (1) becomes

$(2). \: \:IR= \dfrac{\Delta \Phi_B}{\Delta t }.$

(a).

We are told that the change in magnetic flux is $\Phi_B = 30Tm^2$ , the current induced is $I = 40A$ , and the resistance of the wire is $R = 2.5\Omega$ ; therefore, equation (2) gives

$(40A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },$

which we solve for $\Delta t$ to get:

$\Delta t = \dfrac{30Tm^2}{(40A)(2.5\Omega)},$

$\boxed{\Delta t = 0.3s}$ ,

which is the period of time over which the magnetic flux increased.

(b).

Now, if the current had been $I =20A$ , then equation (2) would give

$(20A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },$

$\Delta t = \dfrac{30Tm^2}{(20A)(2.5\Omega)},$

$\boxed{\Delta t = 0.6 s\\}$

which is a longer time interval than what we got in part a, which is understandable because in part a the rate of change of flux $\dfrac{\Delta \Phi_B}{\Delta t}$ is greater than in part b, and therefore , the current in (a) is greater than in (b).

7 0

3 years ago