All categories

4 years ago

How does the energy possessed by a ball bearing change as it travels along an incline ramp?

1 answer:

7 0

Kinetic energy increases, potencial energy decreases,
kinetic energy + potential energy = energy, energy can not be destroyed, just transformed

You might be interested in

What are the units for acceleration?

Anni [7]

The main units for acceleration are <span>the meter per squared second as told by Galileo Galilei. Although there can be more than one example, I consider this one to be correct. Hope it will help you in some measure.</span>

4 0

3 years ago

Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal spee

e-lub [12.9K]

Answer:

r₁ = 20.5 cm

Explanation:

In this exercise we can use the conservation of energy

the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign

starting point.

Em₀ = U_g + U_e + K = $-G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2} m v^2)$

the two in the kinetic energy is because they are two particles

final point. When it is detained

Em_f = U_g + U_e = $-G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}$

the energy is conserved

Em₀ = em_f

the charges and masses of the two particles are equal

$-G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}$

sustitute the values

-6.67-11 (4.5 10-3) ² / 0.25 - 9, 109 (30 10-9) ² / 0.25 + 4.5 10-3 4² = - 6.67 10- 11 (4.5 10-3) ² / r1 -9 109 (30 10-9) ² / r1

-5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁ + 8.1 10⁻⁶ / r₁

We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.

3.24 10⁻⁵ - 7.2 10⁻⁵ = 8.1 10⁻⁶ / r₁

-3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁

r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵

r₁ = 2.045 10⁻¹ m

r₁ = 20.5 cm

4 0

3 years ago

Find the electric field at a point midway between two charges of +40.0 x 10^-9 c and.+60.0 x 10^-9 c

PIT_PIT [208]

Missing part in the text: "...the charges are <span>separated by a distance of 30.0 cm."
</span>
Solution:
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
$E=k_e \frac{q}{r^2}$
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).

Let's calculate the electric field generated by the first charge:
$E_1 = (8.99 \cdot 10^9 Nm^2 C^{-2} ) \frac{+40.0 \cdot 10^{-9} C}{(0.15 m)^2}=1.6 \cdot 10^4 N/C$

While the electric field generated by the second charge is
$E_2 = (8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{+60.0 \cdot 10^{-9} C}{(0.15 m)^2}=2.4 \cdot 10^4 N/C$

Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
$E=E_2 - E_1 = 2.4 \cdot 10^4 N/C - 1.6 \cdot 10^4 N/C = 8000 N/C$

4 0

3 years ago

State the general relationship among temperature, pressure, and depth in the ocean.

user100 [1]

Answer: Temperature is directly proportional to the depth inside Earth. In simple terms, it means the temperature increases as the depth increases inside

Explanation: Hoped this helped :)

3 0

3 years ago

To drive defensively means taking proactive measures to avoid accident situations regardless of their potential causes.

oksian1 [2.3K]

Answer:

True

Explanation:

defines defensive driving skills can be seen as driving with a conscious mindset, in order save lives, time, and money, in spite of the conditions around you and the actions of others.

It entails taking proactive measures such avoiding oncoming speeding vehicles, making sure you can see the rear tires of the vehicle in front of you in a traffic jam, always obeying traffic rules. This is done to protect the lives and property of both yourself and the people around you, regardless of he conditions that you are faced with while driving.

5 0

3 years ago