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3 years ago

How does the energy possessed by a ball bearing change as it travels along an incline ramp?

1 answer:

7 0

Kinetic energy increases, potencial energy decreases,
kinetic energy + potential energy = energy, energy can not be destroyed, just transformed

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For a freely falling object dropped from rest, what is the acceleration at the

Zinaida [17]

The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

initial velocity of the object, u = 0
time of motion of the object, t = 3 seconds

Acceleration is the change in velocity per change in time of motion.

The acceleration of the object after 3 seconds of fall is calculated as follows;

Since the object is in free fall, the object experiences only acceleration due to gravity.
the magnitude of this acceleration due to gravity is 9.8 m/s²
the direction of this acceleration is downwards

Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

7 0

2 years ago

A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel

Goryan [66]

Answer:

Part a)

$V' = 7.77 Volts$

Part b)

$k' = 6.27$

Explanation:

As we know that capacitor plate is connected across 2.1 V and after charging it is disconnected from the battery

So here we can say that charge on the plates will remain conserved

So we will have

$Q = kC(2.1)$

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

$V' = \frac{Q}{C'}$

$V' = \frac{kC(2.1)}{C}$

$V' = 3.7 \times 2.1$

$V' = 7.77 Volts$

Part b)

Now the capacitor plates are again isolated and unknown dielectric is inserted between the plates

So again charge is same so potential difference is given as

$V" = \frac{Q}{k'C}$

$0.59 V = \frac{kCV}{k'C}$

$0.59 = \frac{3.7}{k'}$

$k' = 6.27$

5 0

2 years ago

When light of wavelength 160 nm falls on a gold surface, electrons having a maximum kinetic energy of 2. 66 ev are emitted. Find

enyata [817]

When the light of wavelength is falling on gold surface, the electrons begin to exchange energies.

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀ =1.231 × 10¹⁵ Hz

<h3>What is work function?</h3>

The energy needed for a particle to escape and break through the surface.

The kinetic energy of the light emitted is 2.66 eV and wavelength of the light is 160 nm = 160 × 10⁻⁹ m.

a) The work function of the gold for given maximum kinetic energy is

Φ = hc / λ - K.Emax

Substituting 6.626 × 10⁻³⁴ J.s for h, 3 × 10⁸ m/s for c and 2.66 eV for K.Emax, work function will be

Φ =8.16 × 10⁻¹⁹ J

1 eV = 1.6 × 10⁻¹⁹

The work function in eV is Φ =5.097 eV.

b) The cutoff wavelength is related to work function as

λ₀ = hc / Φ

Substitute the corresponding values into the equation, we get the cut off wavelength

λ₀ = 243.71 nm

c) The frequency corresponding to the cut-off wavelength is

ν₀ = c / λ₀

Substitute the corresponding values into the equation, we get the frequency,

ν₀ =1.231 × 10¹⁵ Hz

Therefore, the values for the following are

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀ =1.231 × 10¹⁵ Hz

Learn more about wave function.

brainly.com/question/17484291

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3 0

1 year ago

Electrons in an atom make up most of the _________ of the atom, while the protons and neutrons make up nearly all of the _______

Vinvika [58]

Answer:

volume;mass

Explanation:

3 0

2 years ago

Read 2 more answers

During a hurricane in 2008, the Westin Hotel in downtownNew Orleans suffered damage. Suppose a piece of glass dropped near the t

tangare [24]

Answer:

<u>77.8 m/s, downward</u>

Explanation:

For uniform acceleration motion, the average speed is equal to half the soum of the initial velocity, Vi, and the final velocity, Vf

Average speed = (Vf + Vi)/2

Also, by definition, the average speed is the distance divided by the time:

Average speed = distance / time

Then:

(Vf + Vi)/2 = 300m/6.62s

Other kinematic equation for uniform acceleration is:

Vf = Vi + a×t

Since the window is falling and the air resistance is ignored, a = g (gravitational acceleration ≈ 9.8m/s²)

Replacing the known values we can set a system of two equations:

From (Vf + Vi)/2 = 300m/6.62s

(Vf + Vi) = 2 × 300m/6.62s

Vf + Vi = 90.634 equation 1

From Vf = Vi + a×t

Vf - Vi = 9.8 (6.62)

Vf - Vi = 64.876 equation 2

Adding the two equations:

2Vf = 155.510

Vf = 77.8 m/s downward (velocities must be reported with their directions)

8 0

2 years ago