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3 years ago

A person suffering from anaemia gets tired

2 answers:

5 0

Yes, Anaemia is a blood disorder, (I believe of iron levels) and can cause nausea and lightheaded ness, ergo making the victim tired and oxygen hard to reach the brain in some occasions. They can even end up passing out

avanturin [10]3 years ago

4 0

Answer: yes.

Explanation:

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Which statement is true? CTP hydrolysis can be a source of chemical energy. dATP is the most common source of chemical energy in

Gemiola [76]

1. Statement A is true.

When GTP is hydrolysed, the free energy of hydrolyses is used to power or drive reactions that are favourable energetically.

2. Statement B it true.

ATP is a complex chemical that gives energy for the activities in many living cells. During hydrolyses, chemical energy stored in the energy-rich phosphoanhydride is released. Hence its a common source of chemical energy in cells.

3. Statement C is false.

The hydrolyses of ATP to ADP in the presence of phosphate, releases one mole of ATP which is estimated to be -57Kj/mol not 14Kj/mol. Below is the equation;

ATP + H20 -----> ADP + Pi + Free energy.

4. Statement D is false.

GTP stands for guanosine triphosphate.

ATP stands for adenosine triphosphate

ADP stands for adenosine diphosphate.

3 0

4 years ago

You punt a ball straight up at 20 m/s. What is the balls hangtime

Natalija [7]

The hang time of the ball is 4.08 s

Explanation:

The ball is in free fall motion: this means that it is acted upon gravity only, so its acceleration is the acceleration of gravity,

$a=g=-9.8 m/s^2$

downward (the negative sign refers to the downward direction).

Since this is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

First we calculate the time it takes for the ball to reach the maximum height, where the velocity is zero:

v = 0

Substituting:

u = +20 m/s

$a=-9.8 m/s^2$

we find t

$t=\frac{v-u}{a}=\frac{0-20}{-9.8}=2.04 s$

The motion of the ball is symmetrical, so the total time of flight is just twice the time needed to reach the maximum height, therefore:

$T=2t=2(2.04)=4.08 s$

Learn more about free fall:

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#LearnwithBrainly

4 0

3 years ago

A rocket is fired vertically upward. At the instant it reaches some altitude with a speed of 100 m/s. It explodes into three fra

docker41 [41]

Answer:

The magnitude of the velocity of the third fragment is 212.13 m/s.

Explanation:

Given that,

Speed = 100 m/s

Vertical speed of first fragment = 150 m/s

Vertical speed of second fragment = 150 m/s

We need to calculate the vertical speed of third fragment

Using conservation of momentum

$P_{iy}=P_{fy}$

$mv=\dfrac{m}{3}{v_{1}}+\dfrac{m}{3}v_{2}+\dfrac{m}{3}v_{3}$

Put the value into the formula

$m\times100=\dfrac{m}{3}\times150+\dfrac{m}{3}\times0+\dfrac{m}{3}\times v_{y}$

$\dfrac{1}{3}v_{y}=100-50$

$v_{y}=150\ m/s$

We need to calculate the horizontal speed of third fragment

Using conservation of momentum

$P_{iy}=P_{fy}$

$mv=\dfrac{m}{3}{v_{1}}+\dfrac{m}{3}v_{2}+\dfrac{m}{3}v_{3}$

Put the value into the formula

$m\times0=\dfrac{m}{3}\times0+\dfrac{m}{3}\times150+\dfrac{m}{3}v_{x}$

$\dfrac{1}{3}v_{x}=-50$

$v_{x}=-150\ m/s$

We need to calculate the magnitude of the velocity of the third fragment

$v=\sqrt{v_{x}^2+v_{y}^2}$

Put the value into the formula

$v=\sqrt{(-150)^2+(150)^2}$

$v=212.13\ m/s$

Hence, The magnitude of the velocity of the third fragment is 212.13 m/s.

7 0

3 years ago

If the specific heat of a metal is 0.850 J/g °C, what is its atomic weight?

Liula [17]

As we know that with respect to oxygen atom taken as reference the product of atomic mass and specific heat of a metal will remain constant.

this product is equal to 0.38

so here we will say that let atomic mass of the metal is M

so with respect to oxygen atom its mass is given as

$m = \frac{M}{16}$

now we will have

$\frac{M}{16} \times 0.850 = 0.38$

now we will have

$M = 7$

so atomic mass of the metal is 7 g/mol

8 0

4 years ago

Read 2 more answers

Four positive charges of magnitude q are ar- ranged at the corners of a square, as shown. At the center C of the square, the pot

andre [41]

Answer:

Explanation:

Let the four charges is q and the side of square is a.

Let the distance of all charges from the centre is d.

AO = BO = CO = DO = d

Potential due to single charge at the centre is Vo.

$V_{o}=\frac{Kq}{d}$

Potential at the centre due to all charges is

V = Vo + Vo + Vo + Vo = 4 Vo

Electric field due to single charge at centre is Eo.

So, the electric ifled due to all charges at centre is

E = (Eo - Eo) + (Eo - Eo) = 0

7 0

3 years ago

A person suffering from anaemia gets tired​

A person suffering from anaemia gets tired