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3 years ago

A person suffering from anaemia gets tired

2 answers:

5 0

Yes, Anaemia is a blood disorder, (I believe of iron levels) and can cause nausea and lightheaded ness, ergo making the victim tired and oxygen hard to reach the brain in some occasions. They can even end up passing out

avanturin [10]3 years ago

4 0

Answer: yes.

Explanation:

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A 230-km-long high-voltage transmission line 2.0 cm in diameter carries a steady current of 1,100 A. If the conductor is copper

Molodets [167]

Answer:

28.23 years

Explanation:

I = 1100 A

L = 230 km = 230, 000 m

diameter = 2 cm

radius, r = 1 cm = 0.01 m

Area, A = 3.14 x 0.01 x 0.01 = 3.14 x 10^-4 m^2

n = 8.5 x 10^28 per cubic metre

Use the relation

I = n e A vd

vd = I / n e A

vd = 1100 / (8.5 x 10^28 x 1.6 x 10^-19 x 3.14 x 10^-4)

vd = 2.58 x 10^-4 m/s

Let time taken is t.

Distance = velocity x time

t = distance / velocity = L / vd

t = 230000 / (2.58 x 10^-4) = 8.91 x 10^8 second

t = 28.23 years

5 0

3 years ago

Read 2 more answers

To make the next delivery, Sam-I-Am goes 45 mi/h for 2 hours. How far did he travel in that time?

andrezito [222]

Hello =D

This problem is about cinematic

V = 45 mi/h

t = 2 h

Then

V= X/t

X = V*t

Then

X = (45)*(2)

X = 90 mi

Best regards

5 0

2 years ago

What is the ACCELERATION of a 50 kg object pushed with a force of 500 newtons *

Anon25 [30]

Answer:

The answer is

Explanation:

To find the acceleration of an object given the force and mass we use the formula

<h3> $acceleration = \frac{force}{mass}$ </h3>

From the question

mass of object = 50 kg

force = 500 N

So the acceleration is

<h3> $acceleration = \frac{500}{50} \\ = \frac{50}{5}$ </h3>

We have the final answer as

Hope this helps you

5 0

3 years ago

A car is 200 m from a stop sign and traveling toward the sign at 40.0 m/s. At this time, the driver suddenly realizes that she m

victus00 [196]

Answer:

The acceleration of the car will be $a=9600m/sec^$

Explanation:

We have given that distance from stop sign s = 200 m

Time t = 0.2 sec

We have to find the constant acceleration

Now from second equation of motion $s=ut+\frac{1}{2}at^2$

$200=40\times 0.2+\frac{1}{2}\times a\times 0.2^2$

$a=9600m/sec^$

So the acceleration of the car will be $a=9600m/sec^$

6 0

3 years ago

What important characteristics of planets and moon are studied by astronomers?

kondor19780726 [428]

mass density orbit time temperature surface conditions

distyance from sun

5 0

2 years ago

A person suffering from anaemia gets tired​

A person suffering from anaemia gets tired