I think d would be the answer.
Answer:
1. 21.66 Ohms
2. 3.38 A
3. 6.7 V
Explanation:
1. Req = 6+2 = 8 Ohms (2 and 6 are in a series circuit)
Req = 1/8 +1/4 = 3/8 = 8/3 = 2.66 Ohms (8 and 4 are parallel, so we will add them using this equation)
Req = 2.66 + 1 + 9 + 3 + 6 = 21.66 Ohms
2. I = V/R = 9/2.66 = 3.38 A (In a series circuit, the current is the same across the resistors, so we will add them and divided them by 9 volts)
3. V = IR = 3.38 x 2 = 6.7 V (In a series circuit, the voltage is different, so each resistor will have a different voltage.)
I hope this helps. I am not an expert in physics but its ok :)
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Yes
Explanation:
It is a reasonable result obtained.
Error = true value - measured value
true value = 24.5
measured value = 24.2
Error = 24.5 - 24.2 = 0.3g
The error reported in the reading is 0.3g
The reason why we had a disparity in the figures obtained from this measurement is primarily due to some erroneous scale.
The mixture at the end of the day is a solution.
We are expected to have the same mass but due to experimental or some form of random error introduced, we noticed a difference.
The value obtained is quite logical as we only had a deviation of 0.3g.
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Error brainly.com/question/2764830
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Answer:
Mirages happen when the ground is very hot and the air is cool.
Explanation:
They happen when light passes through two layers of air with different temperatures. The desert sun heats the sand, which in turn heats the air just above it. The hot air bends light rays and reflects the sky.
When you see it from a distance, the different air masses colliding with each other act as a mirror.
To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".
The overall magnification of microscope is
Where
N = Near point
l = distance between the object lens and eye lens
= Focal length
= Focal of eyepiece
Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm
Replacing,
Therefore the correct answer is C.
