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Pavel [41]
3 years ago
14

Ashkon throws a basketball across the court to his teammate. The ball has 57 J of potential energy and 61 J of kinetic energy. W

hat is the total mechanical energy of the basketball?
Physics
2 answers:
Gwar [14]3 years ago
8 0
The total mechanical energy of the ball is the sum of its potential energy U and its kinetic energy K, therefore:
E=U+K=57 J+61 J=118 J
so, the total mechanical energy of the basketball is 118 J.
s2008m [1.1K]3 years ago
7 0

The total mechanical energy of the ball is the sum of its potential energy U and its kinetic energy K, therefore:

E=U+K=57 J+61 J=118 J

so, the total mechanical energy of the basketball is 118 J.

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To solve this problem, you must figure out (in vector form) both the wind vector and plane vector

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w⃗ +P⃗ ,

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ground speed=||w⃗ +P⃗ ||

 

Using the planar representation of your situation, this will help you understand the equation, use this to make the equation more understandable.

w⃗ =AB¯¯¯¯¯¯¯¯,   P⃗ =AC¯¯¯¯¯¯¯¯

 

the smaller circle is of radius 50 (similar to the wind speed) and the larger circle is of radius 200 (similar to the plane vector.  To get the coordinates of these two vectors,  use polar coordinates.

Let East be 0 degrees, so since the wind vector is on the circle of radius 50, we have:

w⃗ =⟨50cos(135),50sin(135)⟩=⟨−252√, 252√⟩.

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w⃗ +P⃗ =⟨100−252√ , 1003√+252√⟩

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8 0
3 years ago
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4 0
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4 0
3 years ago
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Answer:

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equation (1)/(2)

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