The acceleration of the rocket will be "56.2 m/s²".
According to the question,
The initial speed during launch,
The speed at fuel running out point,
= 375 m/s
Height,
= 1250 m
As we know,
→ 
or,
→ 
By putting the values, we get
→ 
→ 
→ 
Thus the above solution is correct.
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brainly.com/question/11038449
<span>We first calculate the velocity of the ball when it hits the ground; this is equal to the square root of the quantity (2*g*d) where g is the acceleration of gravity (9.8 m/s^2) and d is the distance fallen, 1.5m.
So, we get a velocity of sqrt(2*9.8*1.5) = 5.42 m/s.
We can calculate the impulse force applied to the putty ball by using Newton's second law, which states that the applied force is equal to the product of mass and acceleration, where acceleration can be further decomposed as the change in velocity divided by the change in time. Thus, inputting the known values, we have:
F = ma = m(dv/dt) = 1.0*5.42/0.045 = 120.4 newtons.</span>
Answer:
w = -0.475N
Explanation:

To get Va and Vb

R = 0.525 m
m = 0.0350 kg
g = 9.8 m/s²

K.Ea = 0.5 * 0.035 * 7.25²
K.Ea = 0.92 J
Since point A is at the bottom of the path, h = 0 m
P.Ea = 0 m
For Vb







Answer:
1. 2.5s
Explanation:
1. For time, divide Distance / speed
25m / 10
=2.5s