Answer:
Efficiency = 52%
Explanation:
Given:
First stage
heat absorbed, Q₁ at temperature T₁ = 500 K
Heat released, Q₂ at temperature T₂ = 430 K
and the work done is W₁
Second stage
Heat released, Q₂ at temperature T₂ = 430 K
Heat released, Q₃ at temperature T₃ = 240 K
and the work done is W₂
Total work done, W = W₁ + W₂
Now,
The efficiency is given as:

or
Work done = change in heat
thus,
W₁ = Q₁ - Q₂
W₂ = Q₂ - Q₃
Thus,

or

or

also,

or

thus,

thus,

or

or
Efficiency = 52%
<h2>Answer</h2>
1m/s
<h2>Explanation</h2>
Given that:
<em>Mass of first blob = 2kg = m1</em>
<em>Velocity of blob = 4m/s = v1</em>
<em>Mass of second blob = 6kg = m2</em>
<em>Velocity of blob = 0m/s = v2</em>
<em />
To find:
<em>Final velocity = Vf</em>
<em />
<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>
<em />
<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>
(2*4) + (6*0) = Vf(2+6)
8 + 0 = Vf(8)
8 = Vf(8)
Vf = 1 m/s
So the speed of two blobs immediately after colliding = 1 m/s
Sliding and Static.
Would be the right one here.
KE= 1/2MV^2 - equation
KE= 1/2 (2 kg)(15 m/s)^2 - plug it to the equation
KE= (1 kg)(225 m/s) - multiply
KE= 225 J - Answer (letter D)
Hope this helps