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olganol [36]
2 years ago
13

Models are particularly useful in relativity and quantum mechanics, where conditions are outside those normally encountered by h

umans. What is a model?
Physics
1 answer:
mylen [45]2 years ago
4 0

Answer:

A model is defined as a structure used to represent an object, usually of a different scale.

Explanation:

In quantum mechanics and particle physics, many of the particles are subatomic, meaning that they are smaller than atoms. This is where a model would be useful. A model could help people to visualise what the particle looks like, and in general would make it easier to understand the behaviour of such a particle.

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With the simplified model of the eye, what corrective lens (specified by focal length as measured in air) would be needed to ena
Ymorist [56]

Answer:

Please see the attached picture for the complete answer.

Explanation:

6 0
3 years ago
Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution
Lera25 [3.4K]

Answer:

The mass of the solution is 120 g.

Explanation:

The mass of the solution is given by:

m_{sol} = m_{1} + m_{2}

Where:

m_{sol}: is the mass of the solution

m_{1}: is the mass of the solvent

m_{2}: is the mass of the solute

In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.          

Hence, the mass of the solution is:

m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g  

I hope it helps you!                  

7 0
2 years ago
Two bikers are riding a circular
OverLord2011 [107]
ANSWER.no cause they have to be going a the same speed and I doubt that are gonna go at the same speed.
8 0
2 years ago
The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Dete
oksian1 [2.3K]

Answer:

The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

The shear stress at a distance 0.5-in away from the pipe wall is 0

Explanation:

Given;

pressure drop per unit length of pipe = 0.6 psi/ft

length of the pipe = 12 feet

diameter of the pipe = 1 -in

Pressure drop per unit length in a circular pipe is given as;

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\

make shear stress (τ) the subject of the formula

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}

Where;

τ is the shear stress on the pipe wall.

ΔP is the pressure drop

L is the length of the pipe

r is the distance from the pipe wall

Part (a) shear stress at a distance of  0.3-in away from the pipe wall

Radius of the pipe = 0.5 -in

r = 0.5 - 0.3 = 0.2-in = 0.0167 ft

ΔP = 0.6 psi/ft

ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2

Part (b) shear stress at a distance of  0.5-in away from the pipe wall

r = 0.5 - 0.5 = 0

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0}{2*12} =0

3 0
3 years ago
The angle of incidence of a light beam in air onto a reflecting surface is continuously variable. The reflected ray is found to
Mariana [72]

Answer:

  n = 2.0686

Explanation:

When an unpolarized ray of light is reflected on a surface, the reflected ray is partially polarized, complete polarization occurs when it is true that between the transmitted and reflected ray one has 90, the relationship is

        n = so tea

 let's calculate

        n = tan 64.2

        n = 2.0686

8 0
3 years ago
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