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olganol [36]
3 years ago
13

Models are particularly useful in relativity and quantum mechanics, where conditions are outside those normally encountered by h

umans. What is a model?
Physics
1 answer:
mylen [45]3 years ago
4 0

Answer:

A model is defined as a structure used to represent an object, usually of a different scale.

Explanation:

In quantum mechanics and particle physics, many of the particles are subatomic, meaning that they are smaller than atoms. This is where a model would be useful. A model could help people to visualise what the particle looks like, and in general would make it easier to understand the behaviour of such a particle.

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xxTIMURxx [149]

Answer-

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7 0
3 years ago
A 2.00-gram air inflated balloon is given an excess negative charge, q1 = -3.25 × 10-8 C, by rubbing it with a blanket. It is fo
Llana [10]

Answer:

The rod`s charge must be positive,  because the gravity force is pointing downwards and the electrostatic force must be pointing upwards (in order to balance the gravity force)

The charge is q_2 = 1.667 times 10^(-7) C

Explanation:

F_e = F_g

where F_g = m g and F_e= (1/4 pi e_0)*(q_1*q_2)/d^2,

please see the file attached for more details.

Download pdf
3 0
3 years ago
An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char
ArbitrLikvidat [17]

Answer:

Part a)

W = 1.58 \times 10^{-20} J

Part b)

v = 1.86 \times 10^5 m/s

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = 4.00 \times 10^{-12} C/m^2

now the electric field is given as

E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}

E = 0.225 N/C

Now acceleration of an electron due to this electric field is given as

a = \frac{eE}{m}

a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}

a = 3.97 \times 10^{10}

Now work done on the electron due to this electric field

W = F.d

d = 0.470 - 0.03

d = 0.44 m

So work done is given as

W = (ma)(0.44)

W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)

W = 1.58 \times 10^{-20} J

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

W = \frac{1}{2}mv^2 - 0

1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2

v = 1.86 \times 10^5 m/s

7 0
3 years ago
A 120 W lightbulb and a 90 W lightbulb each operate at a voltage of 120 V. Part A Which bulb carries more current? Which bulb ca
uysha [10]

Answer:

120 W lightbulb

Explanation:

Let the two lightbulb be A and B respectively.

Given the following data;

Power A = 120W

Power B = 90W

Voltage = 120V

To find the current flowing through each lightbulb;

a. For lightbulb A

Power = current * voltage

120 = current * 120

Current = 120/120

Current = 1 Ampere.

b. For lightbulb B

Current = power/voltage

Current = 90/120

Current = 0.75 Amperes

Therefore, the lightbulb that carries more current is A with 1 Ampere.

7 0
3 years ago
A fighter plane is flying overhead at mach 1.50. What angle does the wave front of the shock wave produced make relative to the
olga2289 [7]

Answer:

 θ = 41.80°

Explanation:

Given that

Mach number M= 1.5

We know that

M = u/c

Where c is the velocity of sound and u is the speed of plane

c= 340 m/s

So

u = 1.5 x 340 m/s

u = 510 m/s

We know that

sin\theta =\dfrac{c}{u}

Now by putting the values

sin\theta =\dfrac{c}{u}

sin\theta =\dfrac{340}{510}

 θ = 41.80°

So the angle will be 41.80°.

8 0
3 years ago
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