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olganol [36]
3 years ago
13

Models are particularly useful in relativity and quantum mechanics, where conditions are outside those normally encountered by h

umans. What is a model?
Physics
1 answer:
mylen [45]3 years ago
4 0

Answer:

A model is defined as a structure used to represent an object, usually of a different scale.

Explanation:

In quantum mechanics and particle physics, many of the particles are subatomic, meaning that they are smaller than atoms. This is where a model would be useful. A model could help people to visualise what the particle looks like, and in general would make it easier to understand the behaviour of such a particle.

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Which statement is correct? Theories are accepted as true when a single experiment yields similar results to another one. When a
levacccp [35]
The third statement is correct.

3 0
3 years ago
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An infinitely long cylindrical insulating shell of inner radius a and outer radius b has a uniform volume charge density p. Dete
xenn [34]

Answer: The electric field is: a) r<a , E0=; b) a<r<b E=ρ (r-a)/εo;

c) r>b E=ρ b (b-a)/r*εo

Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.

As we know,

∫E.dr= Qinside/εo

For r<a --->Qinside=0 then E=0

for a<r<b er have

E*2π*r*L= Q inside/εo       in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L

E*2π*r*L =ρ*2*π*r* (r-a)*L/εo

E=ρ*(r-a)/εo

Finally for r>b

E*2π*r*L =ρ*2*π*b* (b-a)*L/εo

E=ρ*b* (b-a)*/r*εo

3 0
3 years ago
You plug in an extension cord and you have to be very careful around electrical outlet. However you can handle his extension cor
IrinaVladis [17]
The second one because you don't get shocked by plugging in something you can get electricted by putting something thin in the outlet then it will send a shock to your hand
4 0
3 years ago
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PLZ HELP
Nadya [2.5K]

1) The mass of the continent is 3.3\cdot 10^{21}kg

2) The kinetic energy of the continent is 1683 J

3) The speed of the jogger must be 6.57 m/s

Explanation:

1)

The continent can be represented as a slab of size

d=5850 km = 5.85\cdot 10^6 m

and depth

t = 35 km = 3.5\cdot 10^4 m

So its volume is

V=d^2 t = (5.85\cdot 10^6)^2(3.5\cdot 10^4)=1.20\cdot 10^{18} m^3

We also know that the density of the continent is

\rho = 2750 kg/m^3

Therefore, we can calculate its mass as:

m=\rho V=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg

2)

The kinetic energy of the continent is given by

K=\frac{1}{2}mv^2

where

m is its mass

v is its speed

We have already calculate its mass, while the speed is

v = 3.2 cm/year

We have to convert into SI units first, as follows:

v=3.2 \frac{cm}{year} \cdot \frac{1}{100 cm/m} \cdot \frac{1}{(365 d/y)(24h/d)(60min/h)(60 s/min)}=1.01\cdot 10^{-9} m/s

The mass is

m=3.3\cdot 10^{21} kg

So, the kinetic energy of the continent is

K=\frac{1}{2}(3.3\cdot 10^{21})(1.01\cdot 10^{-9})^2=1683 J

3)

Here we have a jogger having the same kinetic energy of the continent, so

K=1683 J

And the kinetic energy of the jogger can be expressed as

K=\frac{1}{2}mv^2

where

m = 78 kg is the mass of the jogger

v is his speed

We can therefore re-arrange the equation to find the speed of the man, and we get:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(1683)}{78}}=6.57 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

8 0
3 years ago
A car of mass 1000 kg travelling at a velocity of 25 m/s collides with another car of mass 1500kg which is at rest. The two cars
Svetach [21]

Answer:

<em>The velocity of the two cars is 10 m/s after the collision.</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, the law of conservation of linear momentum  takes the form:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}

\displaystyle v'=\frac{25000}{2500}

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

4 0
3 years ago
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