Which could be the function?
2 answers:
Answer:
Step-by-step explanation:
we have that
The axis of symmetry shown in the graph is x=4
we know that
The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex
so
<em>Verify each case</em>
<em>case a)</em> we have
The vertex is the point (-4,0)
therefore
Cannot be the function
<em>case b)</em> we have
The vertex is the point (0,4)
The axis of symmetry is x=0
therefore
Cannot be the function
<em>case c)</em> we have
The vertex is the point (4,0)
The axis of symmetry is x=4
therefore
Could be the function
<em>case d)</em> we have
The vertex is the point (0,-4)
The axis of symmetry is x=0
therefore
Cannot be the function
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Hello,
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1
Answer:
Option d
Step-by-step explanation:
given that a, b, c, and d be non-zero real numbers.
we can factorise this equation by grouping
Equate each factor to 0 to get
Ratio of one solution to another would be
So ratio would be ad/bc
Out of the four options given, option d is equal to this
So option d is right