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liberstina [14]
3 years ago
9

If an electrostatically charged object is placed near other objects what will occur

Physics
1 answer:
bazaltina [42]3 years ago
4 0
<span>If an electrostatically charged object is placed near other objects, </span>it would be attracted to objects with an opposite charge.
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What is the work done if you push a tree with<br> 50 N of force but the tree does not move?
Soloha48 [4]

Answer:

The work done is 0.

Explanation:

The reason no work is done is because the equation W = Fs.

W = work

F= force

s= displacement

In this scenario F = 50 and s= 0

Therefore.

W = 50(0)

W = 0

4 0
3 years ago
Hey, earn points here
navik [9.2K]

Answer:yayyyy

Explanation:

4 0
3 years ago
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On a clear day at a certain location, a 119-V/m vertical electric field exists near the Earth's surface. At the same place, the
IrinaVladis [17]

Answer:

(a) 62.69 nJ/m^3

(b) 1015.22 μJ/m^3

Explanation:

Electric field, E = 119 V/m

Magnetic field, B = 5.050 x 10^-5 T

(a) Energy density of electric field = \frac{1}{2}\varepsilon _{0}E^{2}

          =\frac{1}{2}\times 8.854\times 10^{-12}\times 119\times 119

          = 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3

(b) energy density of magnetic field = \frac{B^{2}}{2\mu _{0}}

=\frac{\left ( 5.05\times 10^{-5} \right )^{2}}{2\times 4\times 3.14\times 10^{-7}}

= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3

8 0
3 years ago
How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes
cricket20 [7]

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity g=9.81m/sec^2

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

8=2\times 3.14 \sqrt{\frac{l}{9.81}}

l=3.987m

So length of the pendulum will be 3.987 m

3 0
3 years ago
How does the force of gravity exerted
givi [52]

The two forces of gravity are equal

Explanation:

We can answer this question by applying Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In this problem, we can identify the Sun as object A and the Earth as object B. This means that the force of gravity exerted by the Sun on the Earth is the action, while the force of gravity exerted by the Earth on the Sun is the reaction: according to Newton's third law, these two forces are equal and opposite.

Therefore, the two forces of gravity are equal in magnitude, which is given by:

F=\frac{GMm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the Earth

r is the separation between the Earth and the Sun

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

8 0
3 years ago
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