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faust18 [17]
3 years ago
5

The laws of reflection holds for__

Physics
2 answers:
RSB [31]3 years ago
5 0

Answer:

c)both

Explanation:

The laws of reflection hold true for all the reflecting surfaces either spherical or plane. Therefore, the plane mirror, concave mirror and the convex mirror all will follow the laws of reflection.

Galina-37 [17]3 years ago
4 0

Answer:

It holds for only plane mirrors

<em>It</em><em> </em><em>states</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>incidence</em><em> </em><em>is</em><em> </em><em>equal to the </em><em>angle</em><em> </em><em>of</em><em> </em><em>reflect</em><em>ion</em><em>.</em>

This is only possible in plane mirrors only

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For the electric circuit given below, calculate: 3 (i) the equivalent resistance of the circuit, (ii) the total current drawn fr
Daniel [21]

Answer:

1)31/3Ω

2)18/31A

3)4.06V

Explanation:

According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below

1/R= 1/R1 + 1/R2

But we know R1= 5 Ω and R2= 10 Ω

1/R= 1/5 + 1/10

R= 10/3 Ω

=3.33 Ω

Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then

Req = 10/3 +7

Req= 31/3 Ω

Therefore, equivalent resistance = 31/3 Ω

According to ohms law we know that V= IR

Then I= V/R

Where I= current

R= resistance

V= voltage

I= 6/(31/3)

I= 18/31A

We can now calculate the voltage accross the resistor which is

V=(18/31)× 7

V=4.06V

Therefore, the voltage accross the 7 ohm resistor is 4.06V

CHECK THE FIQURE AT THE ATTACHMENT

3 0
3 years ago
The term time dilation refers to which effect?
RoseWind [281]
Is the apparent loss of time of a moving clock as observed by a stationary observer. Thats what i think.
6 0
4 years ago
Read 2 more answers
Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second
Pie

Answer:

Yes, the paths of the two particles cross.

Location of path intersection = ( 1 , 2 , 3)

Explanation:

In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.

So, we can name the time of the first particle T_F ,  and the time of the second particle T_S.

Setting the locations equal, we get the following equations to solve for T_F and T_S:

(-1 + T_F) = (-7 + 2T_S)                     Equation 1

(4 - T_F) = (-6 + 2T_S)                        Equation 2

(-1 + 2T_F) = (-1 + T_S)                     Equation 3

Solving these three equations simultaneously we get:

T_F = 2 seconds

T_S = 4 seconds

Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.

The point of crossing can be found by using the value of T_F or T_S in the location matrices. Doing this for the first particle we get:

Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )

Location of path intersection = ( 1 , 2 , 3)

5 0
3 years ago
10. The shape of the earth is<br> A taco<br> b. A carrot<br> C. A sphere<br> d. A potato
expeople1 [14]

Answer:

C. A sphere.

Explanation:

I'm 100% sure.

6 0
3 years ago
The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.
Aleks [24]

By definition, centripetal acceleration is given by:

a = \frac{v ^ 2}{r}

Where,

v: tangential disk speed

r: disk radius

Substituting values in the given equation we have:

a =\frac{3.3^2}{0.13}\\a = 83.76923077

Rounding the result we have:

a = 83.8 \frac{m}{s^2}

Answer:

The centripetal acceleration of the disc edge in m/s^2 is:

a = 83.8 \frac{m}{s^2}

3 0
4 years ago
Read 2 more answers
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