Answer:
The natural frequency will be 228.11 rad/sec
Explanation:
We have given Inductance L = 0.048 Henry
And the capacitance C = 0.0004 farad
We have to find natural frequency
When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by ![\omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec](https://tex.z-dn.net/?f=%5Comega%20_0%3D%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B0.048%5Ctimes%200.0004%7D%7D%3D228.21%5C%20rad%2Fsec)
So the natural frequency will be 228.21
Increase the force the engine provides and decrease the mass of the car
Answer:
chris gets 960 and molly gets 1440
Explanation:
add the ratio up and divide
2+3=5
2400/5=480
480x2=960
480x3=1440
960+1440= 2400
D=at²
441m=(5*9.81m/s²)(t²)
t²=441/(5*9.81)
t≈√8.99
t≈3 sec