What is the momentum of a 0.01 kg toy car moving at 5.0 m/s?

The molality of a solution that is made by dissolving a certain mass of benzene in 20.6 g of carbon tetrachloride is 0.529 m. Ho

valentina_108 [34]

You have to multiply .529 and 20.6 to get 10.8974

6 0

4 years ago

Read 2 more answers

Why do atomic model has changed over time

Elenna [48]

The model of the atom has dramatically changed over many many years.We learned atoms make up different substances and are the smallest particles of matter, which have subatomic particles that are very small portions of matter. At first scientist only thought there were electrons which are negatively charged.

8 0

3 years ago

The work of which scientist was most essential to the use of radioactive

fgiga [73]

Answer:

A

Antoine-Laurent Lavoisier

:D

8 0

3 years ago

An atom can be called a particle, but a molecule is never called a particle. True or False ?

ivanzaharov [21]

Answer: False; it contains particles, but that doesn't mean it's a particle itself.

Hope this help.

5 0

4 years ago

how many grams of calcium oxide will be produced in a closed vessel containing 20.0 kg of calcium and 20.0 kg of oxygen gas if t

sergejj [24]

Answer:

27984.1311 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For calcium :-

Mass of calcium = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of calcium = 40.078 g/mol

Thus,

$Moles= \frac{20000\ g}{40.078\ g/mol}$

$Moles\ of\ calcium= 499.0269\ mol$

For oxygen gas :-

Mass of oxygen gas = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of oxygen gas = 31.999 g/mol

Thus,

$Moles= \frac{20000\ g}{31.999\ g/mol}$

$Moles\ of\ oxygen\ gas= 625.0195\ mol$

According to the given reaction:

$2Ca+O_2\rightarrow 2CaO$

2 moles of calcium reacts with 1 moles of oxygen gas

Also,

1 mole of calcium react with 1/2 mole of oxygen gas

So,

499.0269 mole of calcium react with $\frac{1}{2}\times 499.0269$ mole of oxygen gas

Moles of oxygen gas = 249.5135 moles

Available moles of oxygen gas = 625.0195 moles

Limiting reagent is the one which is present in small amount. Thus, calcium is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

2 moles of calcium produces 2 moles of calcium oxide

So,

1 mole of calcium produces 1 mole of calcium oxide

Also,

499.0269 mole of calcium produces 499.0269 mole of calcium oxide

Moles of calcium oxide = 499.0269 moles

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = Moles × Molar mass = 499.0269 × 56.0774 g = 27984.1311 g

27984.1311 g of calcium oxide will be produced.

8 0

3 years ago