The mass of the water is 1580 g.
<h3>What is the amount of water formed?</h3>
We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from 7.9 x 10-3 atm to 1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.
Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm
Using;
PV = nRT
n = PV/RT
n = 7.78 * 10^-3 atm * 2.4 x10^5 l/0.082 * (39 + 273)
n = 85 moles
Since 1 mole of carbon dioxide produces 1 mole of water
85 moles of carbon dioxide produces 85 mole of water
Mass of water produced = 85 mole * 18 g/mol
= 1580 g
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Answer: ![R=4.82436 \frac{Pa. m^{3}}{mol. K}](https://tex.z-dn.net/?f=R%3D4.82436%20%5Cfrac%7BPa.%20m%5E%7B3%7D%7D%7Bmol.%20K%7D)
Explanation:
The Ideal Gas equation is:
(1)
Where:
is the pressure of the gas
the number of moles of gas
is the gas constant
is the absolute temperature of the gas in Kelvin.
is the volume
It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be
.
However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.
Having this clarified, let's isolate
from (1):
(2)
Where:
is the absolute temperature of the gas in Kelvin.
![V=8.8 dm^{3}=0.0088 m^{3}](https://tex.z-dn.net/?f=V%3D8.8%20dm%5E%7B3%7D%3D0.0088%20m%5E%7B3%7D)
(3)
Finally:
Volume would be 6.79792764 cm³. Just divide 131.2 by 19.3
ρ=Mass/Volume
Volume= mass/density
Answer:
Halogen Family of elements
Explanation:
Group Seventeen
Answer:
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.
2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.
Explanation:
The molecular formula of boron trifluoride is
.
So, one mole of boron trifluoride has one mole of boron atoms.
1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.
The number of atoms in 2.20 moles of boron is:
One mole of boron has ----
atoms.
Then, 2.20 moles of boron has
-![=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms](https://tex.z-dn.net/?f=%3D2.20%20mol.%20x%206.023%20x%2010%5E2%5E3%20atoms%20%2F1%20mol%5C%5C%3D13.25x10%5E2%5E3%20atoms)
2. Calculate the number of moles of BF3 in 5.35*1022 molecules.
![(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol](https://tex.z-dn.net/?f=%285.35x10%5E2%5E2%20molecules%2F6.023x10%5E2%5E3%29x%201mol%5C%5C%3D0.0888mol)
One mole of boron trifluoride has three moles of fluorine atoms.
Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.
=0.266mol of fluorine atoms.