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JulsSmile [24]
3 years ago
10

A sports car is advertised to be able to stop in a distance of 50.0 m from a speed is 99.0km/h. What is its acceleration in m/s2

?
Physics
1 answer:
Shtirlitz [24]3 years ago
4 0
99.0km/h =27.5m/s (this is the initial speed)
The final speed is zero
The distance is 50.0m
Therefore you use the formula:
vfinal²=vinitial²+2ad
a=(vfinal²-vinitial²)/2d
 = (0²-27.5²)/(2x50.0)
 =-7.5625 or in correct sigdigs -7.56m/s²
Hope this helps!
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241.8 N.

Explanation:

The force on branch provides a reaction to the ape's weight force plus the centripetal force needed to keep the gibbon in a circular motion of radius 0.60 m.

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F = mg + mv²/r

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Find the distance covered by a car in 10 second, if it is moving at the speed of 20m/s​
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Any help with these? I’ve tried to answer some but I’m really confused.
Eva8 [605]

Top left: The slope of the line gives the (constant) acceleration of the moving object because the plot describes the velocity of some moving object. It's hard to tell what points the line passes through in the picture you took, but whatever slope/acceleration you find, that value will stay the same regardless of the time.

Top middle: The slope of the line is negative, which means acceleration has a negative sign. And because the line describes velocity over time, the fact that velocity is linear means that acceleration is constant.

Top right: The acceleration is the slope of the tangent line to the parabola at t=10. You can visually confirm that the slope of this line would be positive. Now, the average velocity between t=10 and t=11 is

\bar a=\dfrac{v(11)-v(10)}{11-10}\approx16-14=2

Judging by the plot, 2\,\dfrac{\mathrm m}{\mathrm s^2} seems like a pretty reasonable choice among the answers.

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Bottom middle: Opposite situation as in [bottom left].

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3 years ago
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