The atomic mass of an atom is determined by which of the following?

2 particles having charges q1=0.500 nC and q2=8.00 nC are separated by a distance of 1.20m. at what point along the line connect

laila [671]

Refer to the figure shown below.

Charge q₁ = 0.5 nC = 0.5x10⁻⁹ C
Charge q₂ = 8 nC = 8x10⁻⁹ C
d = 1.2 m, the distance between the two charges.

x is the distance between the two charges, measured from the charge q₁.

From Coulomb's Law,
The electric field generated along x by q₁ is
E₁ = k(q₁/x²)
The electric field generated along x by q₂ is
E₂ = -k[q₂/(d-x)²]
where
k = 8.988x10⁹ (N-m²)/C² is the Coulomb constant/

When the electric field along x is zero, then
E₁ + E₂ = 0
k[q₁/x² - q₂/(d-x)²] = 0

That is,
0.5/x² = 8/(1.2 - x)²
8x² = 0.5(1.2 - x)²
16x² = 1.44 - 2.4x + x²
15x² + 2.4x - 1.44 = 0

Solve with the quadratic formula.
x = (1/30)*[-2.4 +/- √(5.76 + 86.4)]
= 0.24 or -0.4 m

Reject the negative answer to obtain
x = 0.24 m
d-x = 0.96 m

Answer
The electric field is zero between the charges so that
(a) It is at 0.24 m from the 0.5 nC charge, and
(b) It is at 0.96 m from the 8 nC charge.

7 0

2 years ago

Read 2 more answers

A raft is made of 12 logs lashed together. Each is 45 cm in diameter and has a length of 6.5 m. How many people can the raft hol

tatyana61 [14]

Answer:

324 people

Explanation:

radius r = diameter / 2 = 45cm /2 = 22.5 cm or 0.225 m

We can calculate the total volume of the log by computing the volume of each cylindrical log:

$V = \pi r^2 L = \pi 0.225^2 * 6.5 = 4.6 m^3$

So the total volume of all 12 logs is

$12 * 4.6 = 55.135 m^3$

The weight that the raft can support, is the buoyancy force subtracted by its own weight.

The buoyancy force is basically the weight of the water is displaced, which is water density times volume. The log weight is also log density times its volume

$F = F_b - F_w = g\rho_wV - g\rho_rV = gV(\rho_w - \rho_r)$

where $\rho_w = 1000kg/m^3,\rho_r$ are the density of water and raft, respectively. But since we have the specific gravity of wood is 0.6. That measn

$\rho_r / \rho_w = 0.6$

$\rho_r = 0.6\rho_w$

Therefore $\rho_w - \rho_r = \rho_w - 0.6\rho_w = 0.4\rho_w = 0.4*1000 = 400 kg/m^3$

Let g = 9.8m/s2. We can now calculate the force that the raft can support

$F = gV(\rho_w - \rho_r) = 9.8*55.135*400=216129.2N$

Each person has a mass of 68kg, their weight would be

W = 68*g = 68*9.8 = 666.4N

So the maximum number of people that the raft can hold is

F / W = 216129.2 / 666.4 = 324 people

3 0

3 years ago

Describe what happens to water waves when they strike a flat surface?

shutvik [7]

Answer:

In this case reflection occurs.

Explanation:

This happens when they bounce on objects that they can not pass through.

Hope it helps

okay.

6 0

3 years ago

A river flows due east with a speed of 3.00 m/s relative to earth. The river is 80.0 m wide. A woman starts at the southern bank

babymother [125]

Answer:

48 m

Explanation:

As she travels at the rate of 5m/s due north, the amount of time it would take for her to cross the 80m wide river would be

t = 80 / 5 = 16 seconds

This is also the time it takes for the river to push her to the east side at the rate of 3m/s. So after 16 seconds, she would reach the opposite point at a horizontal distance from her starting of

s = 16*3 = 48 m

4 0

3 years ago

a uniform disc and hollow right circular cone have the same formula for their moment of inertia when rotating about the central

Romashka-Z-Leto [24]

Answer:

This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc

Explanation:

The integration of the differential mass of the hollow right circular cone yields

$I=\int\limits dmr^2 = \int\limits^a_b {\frac{2Mxr^2}{R^2 +H^2} } \, dx = \frac{2MR^2dx}{(R^2 +H^2)^2} \frac{(R^2 +H^2)^2}{4} = \frac{1}{2}MR^2$

and for a uniform disc

I = 1/2πρtr⁴ = 1/2Mr².

6 0

3 years ago