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Shtirlitz [24]
2 years ago
7

Are my answers correct?

Physics
1 answer:
Tema [17]2 years ago
5 0

Explanation:

Your answers to 1 and 4 are correct, and your answer to 5 is half correct.

2. d = ((vf + vi) / 2) t

To solve for t, divide both sides by what's in the parenthesis:

d / ((vf + vi) / 2) = t

If you wish, you can simplify:

t = 2d / (vf + vi)

3. d = vi t + ½ a t²

To solve for a, first subtract vi t from both sides:

d − vi t = ½ a t²

Multiply both sides by 2:

2d − 2 vi t = a t²

Divide by t²:

a = (2d − 2 vi t) / t²

To solve for t when vi = 0, first substitute 0 for vi:

d = (0) t + ½ a t²

d = ½ a t²

Multiply both sides by 2:

2d = a t²

Divide both sides by a:

t² = 2d / a

Take the square root:

t = √(2d / a)

5. Fg = G m₁ m₂ / r²

To solve for r, first multiply both sides by r²:

Fg r² = G m₁ m₂

Divide both sides by Fg:

r² = G m₁ m₂ / Fg

Take the square root;

r = √(G m₁ m₂ / Fg)

Your other answer is correct.

Overall, good effort!

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It is estimated that 26 large pizzas are about right to serve 66 students of a physics club meeting. How many pizzas would be re
Brums [2.3K]

Answer:

The answer to your question is: 15 pizzas

Explanation:

data

26 large pizzas ------ 66 students

? large pizzas --------   38 students

Rule of three

x = 38 (26) / 66 = 14.96 ≈ 15 pizzas

5 0
3 years ago
What is the Difference between accuracy and precision ?<br>​
Pie

Answer:

Accuracy measures how close results are to the true or known value. Precision, on the other hand, measures how close results are to one another.

6 0
2 years ago
Read 2 more answers
A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?
blondinia [14]

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

6 0
3 years ago
Remember to include your data, equation, and work when solving this problem.
andrezito [222]

Answer:

F = 0.00156[N]

Explanation:

We can solve this problem by using Newton's proposed universal gravitation law.

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\

Where:

F = gravitational force between the moon and Ellen; units [Newtos] or [N]

G = universal gravitational constant = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1= Ellen's mass [kg]

m2= Moon's mass [kg]

r = distance from the moon to the earth [meters] or [m].

Data:

G = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1 = 47 [kg]

m2 = 7.35 * 10^22 [kg]

r = 3.84 * 10^8 [m]

F=6.67*10^{-11} * \frac{47*7.35*10^{22} }{(3.84*10^8)^{2} }\\ F= 0.00156 [N]

This force is very small compare with the force exerted by the earth to Ellen's body. That is the reason that her body does not float away.

6 0
2 years ago
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration to a velocity of 13 m/s. What is the magn
olga55 [171]

Answer:

The acceleration is a = 2.75 [m/s^2]

Explanation:

In order to solve this problem we must use kinematics equations.

v_{f} = v_{i} + a*t\\

where:

Vf = final velocity = 13 [m/s]

Vi = initial velocity = 2 [m/s]

a = acceleration [m/s^2]

t = time = 4 [s]

Now replacing:

13 = 2 + (4*a)

(13 - 2) = 4*a

a = 2.75 [m/s^2]

5 0
3 years ago
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