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Shtirlitz [24]
2 years ago
7

Are my answers correct?

Physics
1 answer:
Tema [17]2 years ago
5 0

Explanation:

Your answers to 1 and 4 are correct, and your answer to 5 is half correct.

2. d = ((vf + vi) / 2) t

To solve for t, divide both sides by what's in the parenthesis:

d / ((vf + vi) / 2) = t

If you wish, you can simplify:

t = 2d / (vf + vi)

3. d = vi t + ½ a t²

To solve for a, first subtract vi t from both sides:

d − vi t = ½ a t²

Multiply both sides by 2:

2d − 2 vi t = a t²

Divide by t²:

a = (2d − 2 vi t) / t²

To solve for t when vi = 0, first substitute 0 for vi:

d = (0) t + ½ a t²

d = ½ a t²

Multiply both sides by 2:

2d = a t²

Divide both sides by a:

t² = 2d / a

Take the square root:

t = √(2d / a)

5. Fg = G m₁ m₂ / r²

To solve for r, first multiply both sides by r²:

Fg r² = G m₁ m₂

Divide both sides by Fg:

r² = G m₁ m₂ / Fg

Take the square root;

r = √(G m₁ m₂ / Fg)

Your other answer is correct.

Overall, good effort!

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You are walking from your math class to your science class. You are carrying books
kolezko [41]

Answer:

1800J

Explanation:

Given parameters:

Weight of the book  = 20N

Total distance covered  = 45m + 15m + 30m  = 90m

Unknown:

Total work performed on the books  = ?

Solution:

To solve this problem we must understand that work done is the force applied to move a body through a certain distance.

So;

    Work done  = Force x distance

  Work done  = 20 x 90  = 1800J

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3 years ago
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Simora [160]
You would need to freeze it in a freezer. Hope this helps if it does could I have brainlist thanks
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2 years ago
Read 2 more answers
Show that the units N/kg can be written using only units of meters (m) and second (s). Is this a unit of mass ,acceleration or f
nikdorinn [45]
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2 years ago
a 100g ice cube at 0 degrees celsius is placed in 650 grams of water at 25 degrees celsius. When the mixture reaches equillibriu
Artyom0805 [142]

Answer:

The latent heat of fusion of water is 334.88 Joules per gram of water.

Explanation:

Let the latent heat of ice be 'x' J/g

1) Thus heat absorbed by 100 gram of ice to get converted into water equals

Q_1=100\times x

2) heat energy required to raise the temperature of water from 0 to 25 degree Celsius equals

Q_2=100\times 4.186\times 11=4604.6Joules

Thus total energy needed equals Q_1+Q_2=100x+4604.6

3) Heat energy released by the decrease in the temperature of water from 25 to 11 degree Celsius is

Q_3=650\times 4.186\times (25-11)\\\\Q_{3}=38092.6Joules

Now by conservation of energy we have

Q_1+Q_2=Q_3\\\\100x+4604.6=38092.6\\\\\therefore x=\frac{38092.6-4604.6}{100}=334.88J/g

6 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7
Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

7 0
3 years ago
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