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Shtirlitz [24]
3 years ago
7

Are my answers correct?

Physics
1 answer:
Tema [17]3 years ago
5 0

Explanation:

Your answers to 1 and 4 are correct, and your answer to 5 is half correct.

2. d = ((vf + vi) / 2) t

To solve for t, divide both sides by what's in the parenthesis:

d / ((vf + vi) / 2) = t

If you wish, you can simplify:

t = 2d / (vf + vi)

3. d = vi t + ½ a t²

To solve for a, first subtract vi t from both sides:

d − vi t = ½ a t²

Multiply both sides by 2:

2d − 2 vi t = a t²

Divide by t²:

a = (2d − 2 vi t) / t²

To solve for t when vi = 0, first substitute 0 for vi:

d = (0) t + ½ a t²

d = ½ a t²

Multiply both sides by 2:

2d = a t²

Divide both sides by a:

t² = 2d / a

Take the square root:

t = √(2d / a)

5. Fg = G m₁ m₂ / r²

To solve for r, first multiply both sides by r²:

Fg r² = G m₁ m₂

Divide both sides by Fg:

r² = G m₁ m₂ / Fg

Take the square root;

r = √(G m₁ m₂ / Fg)

Your other answer is correct.

Overall, good effort!

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A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
bekas [8.4K]

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

PV=nRT

Where

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

When the number of moles and volume is constant then the expression can be written as

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Or in practical terms for this exercise depending on the final temperature:

T_2 = \frac{P_2T_1}{P_1}

Our values are given as

T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm

Replacing

T_2 = \frac{(2)(400)}{1}\\T_2 = 800K

Therefore the final temperature of the gas is 800K

6 0
2 years ago
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Sonja [21]

Answer:

I think it is the last one.

Explanation:

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3 years ago
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Studentka2010 [4]
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3 years ago
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pychu [463]

Answer:

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A football punter accelerates a .55 kg football
Ronch [10]

Answer:

17.6 N

Explanation:

The force exerted by the punter on the football is equal to the rate of change of momentum of the football:

F=\frac{\Delta p}{\Delta t}

where

\Delta p is the change in momentum of the football

\Delta t=0.25 s is the time elapsed

The change in momentum can be written as

\Delta p = m(v-u)

where

m = 0.55 kg is the mass of the football

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Combining the two equations and substituting the values, we  find the force exerted on the ball:

F=\frac{m(v-u)}{\Delta t}=\frac{(0.55)(8.0-0)}{0.25}=17.6 N

5 0
3 years ago
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