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algol13
3 years ago
8

What acceleration reaches a car of Formla 1 of 650 Kg of mass whose engine starts with a force of 6000 N

Physics
1 answer:
PtichkaEL [24]3 years ago
4 0
Hope this helps

650 x 6000= 3900000
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Can the tangent line to a velocity vs. time graph ever be vertical? Explain.
34kurt

Answer:

No. Because it would correspond to zero Instantaneous acceleration.

Explanation:

hope this helps

7 0
3 years ago
A traveler first drives 21.0 km east, then 29.1 km southeast, and finally 10.3 km south. Find the traveler's total displacement.
Vinvika [58]

The traveler's total displacement is 53.2 km.

The shortest distance between a particle's starting position and destination is referred to as its displacement vector. Displacement has a distinct physical magnitude than distance. Let's use the motion of a particle making a complete circle as an example. The displacement in this motion is zero, yet the distance traveled is equal to the circle's circumference. The individual displacement vectors are as follows: d1

=22^ikm→d2

= (29.7cos45i29.7sin45) kmd3=104jkm

The traveler's complete disadvantage is,

→d=→d1+→d2+→d3→d

=22^ikM+29.7

cos45^−29.7sin45o) km−10.4^j km→

d=(43^i−31.4^j) km

The magnitude of the total displacement is,

d=√432+31.4/2Km d≈53.2km

The direction is,

θ=tan−1(−31.4/43)

θ=−36.1or 36.1 south of east.

Learn more about displacement here-

brainly.com/question/11934397

#SPJ9

7 0
2 years ago
What sauce goes best with chicky nuggies
Sever21 [200]

Answer:

honey mustard or chick fil a sauce their special sauce

Explanation:

6 0
3 years ago
PLEASE HELPPP :))<br> why do ocean ridges rise above the surrounding ocean floor?
o-na [289]
At the ridge, new crust forms by igneous intrusion and extrusion. Since hot rocks are in a more expanded state and then contract as they cool (as they spread away from the ridge), the midocean ridges stand up high above the surrounding seafloor. The seafloor depth increases with distance away from the midocean ridges.
3 0
3 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
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