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Dovator [93]
4 years ago
7

Review Problem 5.040 For each reaction, identify in order the substance oxidized, the substance reduced, the oxidizing agent, an

d the reducing agent. (a) Cu + 2H2SO4 → CuSO4 + SO2 +2H2O H2SO4; Cu; Cu; H2SO4 Cu; H2SO4; Cu; H2SO4 Cu; H2O; H2O; Cu H2SO4; Cu; H2SO4; Cu Cu; H2SO4; H2SO4; Cu (b) 3SO2 + 2HNO3 + 2H2O → 3H2SO4 + 2NO HNO3; SO2; SO2; HNO3 SO2; H2O; H2O; SO2 SO2; HNO3; HNO3; SO2 HNO3; SO2; HNO3; SO2 SO2; HNO3; SO2; HNO3 (c) 5H2SO4 + 4Zn → 4ZnSO4 + H2S +4H2O H2SO4; Zn; H2SO4; Zn Zn; H2SO4; Zn; H2SO4 H2SO4; Zn; Zn; H2SO4 Zn; H2O; H2O; Zn Zn; H2SO4; H2SO4; Zn (d) I2 + 10HNO3 → 2HIO3 + 10NO2 + 4H2O I2; HNO3; HNO3; I2 HNO3; I2; HNO3; I2 HNO3; I2; I2; HNO3 I2; HNO3; H2O; I2 I2; HNO3; I2; HNO3
Chemistry
1 answer:
alexandr402 [8]4 years ago
8 0

Answer:

A. The correct option is: Cu; H₂SO₄; H₂SO₄; Cu

B. The correct option is: SO₂; HNO₃; HNO₃; SO₂

C. The correct option is: Zn; H₂SO₄; H₂SO₄; Zn

D. The correct option is: I₂; HNO₃; HNO₃; I₂

Explanation:

A chemical reaction that involves the simultaneous transfer of electrons between two chemical species is known as the redox reaction.

In this reaction, a species that gains electrons, thus getting reduced is called the <u>oxidizing agen</u>t. Whereas, species that loses electrons, thus getting oxidized is called the<u> reducing agent</u>.

<u>Oxidation</u> refers to an increase in the oxidation state and <u>reduction</u> refers to a decrease in the oxidation state.

A. Cu + 2H₂SO₄ → CuSO₄ + SO₂ +2H₂O

In this reaction, Cu goes from 0 in Cu to +4 oxidation state in CuSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to +4 oxidation state in SO₂ and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Cu is the reducing agent.

<u>The correct option is: Cu; H₂SO₄; H₂SO₄; Cu</u>

B. 3SO₂ + 2HNO₃ + 2H₂O → 3H₂SO₄ + 2NO

In this reaction, S goes from +4 in SO₂ to +6 oxidation state in H₂SO₄ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +2 oxidation state in NO and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and SO₂ is the reducing agent.

<u>The correct option is: SO₂; HNO₃; HNO₃; SO₂</u>

C. 5H₂SO₄ + 4Zn → 4ZnSO₄ + H₂S +4H₂O

In this reaction, Zn goes from 0 in Cu to +2 oxidation state in ZnSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to -2 oxidation state in H₂S and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Zn is the reducing agent.

<u>The correct option is: Zn; H₂SO₄; H₂SO₄; Zn</u>

D. I₂ + 10HNO₃ → 2HIO₃ + 10NO₂ + 4H₂O

In this reaction, I goes from 0 in I₂ to +5 oxidation state in HIO₃ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +4 oxidation state in NO₂ and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and I₂ is the reducing agent.  

<u>The correct option is: I₂; HNO₃; HNO₃; I₂</u>

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What is paper chromatography? Calculate the Rr value of a colored dye that traveled 52 mm on a chromatography strip while the so
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Answer:

Paper chromatography is a basic technique of chromatography. It consist in the separation of the mixe components using a solvent.

Explanation:

Paper chromatography is a basic technique of chromatography. It consists in the separation of the mixed components using a solvent.

Paper chromatography consists of put some dot of the mix using a glass capillary into a specialized paper, generally made of cellulose, this is called a stationary phase.

Then you put this paper into a camera of glass named, chromatography camera, where previously contain a solvent. The solvent also know as a mobile phase, the type can be defined before the test and involves a study of the kind of the mix, and the compound you want to separate.

The chromatography camera has to be closed all the time during the test, and you can't move at all because the movement of the solvent can alternate the result.

Very often, the solution of the solvent is a mix of different liquid substances with different polarities.

When the stationary phase put into the camera, the solvent starts to move up over the paper, until the separation of the compounds is observable.

the Rf is a value who relates the move of the mobile phase with the move of the distance traveled by the substance tested.

To undersant the paper chromatography, you can watch the images attached.

The first is an image of the chromatography camera.

The second one is an image of a cellulose paper after the chromatography is done. You can watch the dots who indicates the traveling of the compound across the paper.

The third one can show you the evolutions of paper chromatography, from the beginning to the end.

To calculate the Rf value you have to use the equation:

Rf = distance traveled by the substance/distance traveled by the solvent/

<u>Rf = 52mm/81mm =0.64</u>

<u></u>

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Answer:

C. 70%

Explanation:

Atomic Mass of the silicon = 28 g.

Atomic mass of the Carbon = 12 g.

Total mass of the Silicon Carbide = 28 + 12

= 40 g.

Now, Using the formula.

% Composition = Mass of the silicon/Total mass of the compound × 100 %

= 28/40 × 100 %

= 70 %

Hence, % composition of the silicon in SiC is 70%

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