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Dovator [93]
3 years ago
7

Review Problem 5.040 For each reaction, identify in order the substance oxidized, the substance reduced, the oxidizing agent, an

d the reducing agent. (a) Cu + 2H2SO4 → CuSO4 + SO2 +2H2O H2SO4; Cu; Cu; H2SO4 Cu; H2SO4; Cu; H2SO4 Cu; H2O; H2O; Cu H2SO4; Cu; H2SO4; Cu Cu; H2SO4; H2SO4; Cu (b) 3SO2 + 2HNO3 + 2H2O → 3H2SO4 + 2NO HNO3; SO2; SO2; HNO3 SO2; H2O; H2O; SO2 SO2; HNO3; HNO3; SO2 HNO3; SO2; HNO3; SO2 SO2; HNO3; SO2; HNO3 (c) 5H2SO4 + 4Zn → 4ZnSO4 + H2S +4H2O H2SO4; Zn; H2SO4; Zn Zn; H2SO4; Zn; H2SO4 H2SO4; Zn; Zn; H2SO4 Zn; H2O; H2O; Zn Zn; H2SO4; H2SO4; Zn (d) I2 + 10HNO3 → 2HIO3 + 10NO2 + 4H2O I2; HNO3; HNO3; I2 HNO3; I2; HNO3; I2 HNO3; I2; I2; HNO3 I2; HNO3; H2O; I2 I2; HNO3; I2; HNO3
Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0

Answer:

A. The correct option is: Cu; H₂SO₄; H₂SO₄; Cu

B. The correct option is: SO₂; HNO₃; HNO₃; SO₂

C. The correct option is: Zn; H₂SO₄; H₂SO₄; Zn

D. The correct option is: I₂; HNO₃; HNO₃; I₂

Explanation:

A chemical reaction that involves the simultaneous transfer of electrons between two chemical species is known as the redox reaction.

In this reaction, a species that gains electrons, thus getting reduced is called the <u>oxidizing agen</u>t. Whereas, species that loses electrons, thus getting oxidized is called the<u> reducing agent</u>.

<u>Oxidation</u> refers to an increase in the oxidation state and <u>reduction</u> refers to a decrease in the oxidation state.

A. Cu + 2H₂SO₄ → CuSO₄ + SO₂ +2H₂O

In this reaction, Cu goes from 0 in Cu to +4 oxidation state in CuSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to +4 oxidation state in SO₂ and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Cu is the reducing agent.

<u>The correct option is: Cu; H₂SO₄; H₂SO₄; Cu</u>

B. 3SO₂ + 2HNO₃ + 2H₂O → 3H₂SO₄ + 2NO

In this reaction, S goes from +4 in SO₂ to +6 oxidation state in H₂SO₄ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +2 oxidation state in NO and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and SO₂ is the reducing agent.

<u>The correct option is: SO₂; HNO₃; HNO₃; SO₂</u>

C. 5H₂SO₄ + 4Zn → 4ZnSO₄ + H₂S +4H₂O

In this reaction, Zn goes from 0 in Cu to +2 oxidation state in ZnSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to -2 oxidation state in H₂S and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Zn is the reducing agent.

<u>The correct option is: Zn; H₂SO₄; H₂SO₄; Zn</u>

D. I₂ + 10HNO₃ → 2HIO₃ + 10NO₂ + 4H₂O

In this reaction, I goes from 0 in I₂ to +5 oxidation state in HIO₃ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +4 oxidation state in NO₂ and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and I₂ is the reducing agent.  

<u>The correct option is: I₂; HNO₃; HNO₃; I₂</u>

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Answer:

\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

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