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artcher [175]
3 years ago
5

Cathy is using a high-powered microscope to look at a leaf. What does she see?

Chemistry
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

Cells

Explanation:

High-powered microscopes are used in order to see microscopical (extremely small) structures of objects that cannot be seen with a naked eye.

When we look at a leaf, we will see the composition of it and the structural patterns that we couldn't see clearly or at all without a microscope.

Leaves consist of cells and spores (stomata) between the cells. Using a microscope will enable us to see them.

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Which is the first news paper of Nepal​
Airida [17]

Answer:

Nepal Bhasa Patrika

Explanation:

Nepal Bhasa Patrika

3 0
3 years ago
How do you solve this
3241004551 [841]
With your mind. Boom. Lol I'm sorry I don't know I just need points
4 0
3 years ago
Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of hcl with 1,3-pentadiene
GrogVix [38]

1,3-pentadiene has two double bonds which are conjugated, which undergo electrophilic addition reaction on reacting with HCl.

The structure of 1,3-pentadiene is shown in the image.

When strong acid such as HCl reacts with 1,3-pentadiene, the electrophilic addition reaction can occur either on double bond at 1,2-position or at 3,4-position. The reaction that occurs is shown in the image.

3 0
3 years ago
Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a
Mekhanik [1.2K]

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100   ..........(1)

The formula used for relative humidity is:

\text{Relative humidity}=\frac{p_v}{p^o_v}       ...........(2)

where,

p_v = partial pressure of water vapor

p^o_v = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

p=750mmHg

p^o_v=17.5mmHg

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

0.80=\frac{p_v}{17.5mmHg}

p_v=14mmHg

Now we have to calculate the percent humidity by using equation 1.

\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100

\text{Percent humidity}=79.62\%

Therefore, the percent humidity is 79.62 %

4 0
4 years ago
A sample of gold has a mass of 67.2 g and a volume of 3.5 cm3. the density of gold is
scoray [572]
67.2g/3.5cm3= 19.2g/cm3
6 0
3 years ago
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