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3 years ago

Rewrite the equation using Ax+By=C form

Mathematics

2 answers:

cupoosta [38]3 years ago

6 0

Answer:

6x - y = - 6

Step-by-step explanation:

Given

y + 6 = 6(x + 2) ← distribute parenthesis

y + 6 = 6x + 12 ( subtract y from both sides )

6 = 6x - y + 12 ( subtract 12 from both sides )

- 6 = 6x - y OR 6x - y = - 6 ← in the form Ax +By = C

VLD [36.1K]3 years ago

4 0

Step-by-step explanation:

$y + 6 = 6(x + 2) \\ \\ \therefore \: y + 6 = 6x + 12 \\ \\ \therefore \: y = 6x + 12 - 6 \\ \\ \therefore \: y = 6x + 6 \\ \\ \therefore \: - 6x + y = 6 \\ \\ or \: \: \: \: 6x - y = - 6 \\ which \: is \: in \: the \: form \: of \: \\ Ax+By = C \\$

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Which fraction is equivalent to 50%? (in simplest fraction form) A) 1 2 B) 1 4 C) 2 5 D) 4 5

Tatiana [17]

Answer:

1/2 is equivalent to 50%

Step-by-step explanation:

In order to convert a fraction to a percentage you divide the numerator (Top number of a fraction) by the denominator (Bottom number of a fraction), multiply by 100, and add a percentage sign.

So lets try that with our first answer option A) 1/2:

1 divided by 2 = 0.5

0.5 x 100 = 50

50%

So we know that 1/2 is equivalent to 50%

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3 years ago

Is division of whole numbers associative property

SVETLANKA909090 [29]

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3 years ago

Factor completely:<br>64 - y^3

madam [21]

From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is $4^{3}$ , and $y^{3}$ .

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are $a^{3}$ and $b^{3}$ . The difference of those two cubes is:
$a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})$

In our problem, a = 4 (since $a^{3}$ = 64) and b = y (since $b^{3} = y^{3}$ . Plug these values into the rule to find the factor of $64 - y^3$ :
$64 - y^3 \\
= (4 - y)( 4^{2} + 4y + y^{2}) \\
= (4 - y)( 16 + 4y + y^{2})$

-----

Answer: $(4 - y)( 16 + 4y + y^{2})$

8 0

3 years ago

Please Help! 40 Points!

belka [17]

Fyi I didn't find this on google or anything I did the calculation on my computer and yes this is correct...

If it's wrong I'm sorry...