Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
Answer:Luteinizing Hormone
Explanation:Luteinizing Hormone (LH) is a gonadotropin synthesized and secreted by the anterior pituitary gland in response to GnRH. Like FSH, LH is involved in reproductive processes in both males and females. When follicle maturation is complete, an LH surge triggers ovulation.
Typically, the genotype is encoded in the DNA by the gene; this gene in the DNA will then undergo the process of transcription and the information in the gene will be transcripted into mRNA. The mRNA will then undergo the process of translation and the information in the mRNA will be translated into a polypeptide chiefly by the action of ribosome. Thus, bacteria with different genotypes will have different protein which automatically means that they will have different phenotypes.
