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VikaD [51]
3 years ago
10

Given a polynomial f(x), if (x − 4) is a factor, what else must be true?

Mathematics
2 answers:
ollegr [7]3 years ago
3 0

Answer:

f(4)=0


Step-by-step explanation:

<em>The </em><em>Remainder Theorem</em><em> states that when you divide a polynomial f(x)  by a linear factor  (x-a) , where a  is a constant, the remainder is f(x)  evaluated at x=a</em>

<em>Moreover, according to the </em><em>Factor Theorem</em><em>, an extension of the Remainder Theorem, if the remainder of the function f(x) is </em><em>0</em><em> when evaluated at x=a , then (x-a)  is said to be a factor of the polynomial f(x)</em>

Given the 2 theorems above, it follows that if (x-4)  is a factor of f(x) , then the remainder is equal to 0 when f(x) is evaluated at x=4

Which means f(4)=0

Third answer choice is correct.


Ksivusya [100]3 years ago
3 0
If x-a is the factor of f(x) then
f(a) = 0

Hence,
if x-4 is a factor of f(x) then f(4) = 0

option C
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olga55 [171]
Hello!

For every 1 blue marble there are 5 greens

You add the numbers in the ratio

1 + 5 = 6

Divide this number from the amount of marbles

60 / 6 = 10

Multiply the ratio by this

1 * 10 = 10

5 * 10 = 50

There are 10 blue marbles and 50 green ones

The answer is 10

Hope this helps!
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
URGENT!!
Lapatulllka [165]

Answer:

f[g(4)] = 4

Step-by-step explanation:

Given table:

\begin{array}{| c | c | c | c | c | c |}\cline{1-6} x & -6 & -4 & 1 & 3 & 4\\\cline{1-6} f(x) & 4 & -1 & -6 & 1 & 3 \\\cline{1-6} g(x) & 1 & 4 & 3 & -4 & -6 \\\cline{1-6}\end{array}

f[g(4)] is a composite function.

When calculating <u>composite functions</u>, always work from inside the brackets out.

Begin with g(4):  g(4) is the value of function g(x) when x = 4.

From inspection of the given table, g(4) = -6

Therefore, f[g(4)] = f(-6)

f(-6) is the value of function f(x) when x = -6.

From inspection of the given table, f(-6) = 4

Therefore, f[g(4)] = 4

3 0
1 year ago
Read 2 more answers
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