Which force acts between two surfaces to prevent or slow motion

A person weighing 785 newtons on the surface of Earth would weigh 298 newtons on the surface of Mars.

rodikova [14]

Answer:

The gravitational field strength on the surface of Mars = 3.72 m/s²

Explanation:

Gravitational Field Strength: This can be defined as the force per unit mass which is exerted at that point. its direction is the force exerted on a mass in a gravitational field. The S.I unit of gravitational field strength is m/s²

Mathematically, Gravitational field is represented as,

g = F/m ..................... Equation 1.

m = F/g ..................... Equation 2.

Where g = gravitational Field Strength, F = force on the mass, m = mass of the body.

From the question,

Note: That The mass of the object is constant both on the surface of the earth and on the surface of Mars.

On the Surface of the earth,

Given: F = 785 N, g = 9.8 m/s²

Substituting this values into equation 2,

m = 785/9.8

m = 80.10 kg.

On the surface of Mars.

Given: m = 80.10 kg, F = 298.

Substituting into equation 2

g = 298/80.1

g = 3.72 m/s²

Thus the gravitational field strength on the surface of Mars = 3.72 m/s²

3 0

3 years ago

If you were to stand in the exact center of a rotating disc, you would only have what kind of

Dmitriy789 [7]

Answer:

Tangential speed or Rotational speed

3 0

3 years ago

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia

Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0

3 years ago

What is the relationship between Avogadro's number and a mole?

Shtirlitz [24]

Answer:

A. There are 6.02 x 1023 items in a mole, which equals Avogadro's

number

Explanation:

The mole of a substance is

8 0

2 years ago

What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?

suter [353]

Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of $q=1.6 \cdot 10^{-19} C$ , and a mass of $m_p = 1.67 \cdot 10^{-27}kg$ . So, the number of protons is
$N_p = \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24}$ And so the total charge of these protons is $Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C$

So, the neutralize this charge, we must have $N_e$ electrons such that their total charge is
$Q_e = -4.6 \cdot 10^5 C$
Since the charge of each electron is $q_e = -1.6 \cdot 10^{-19}C$ , the number of electrons needed is
$N_e = \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}$
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is $m_e=9.1 \cdot 10^{-31}kg$ , the total mass of electrons should be
$M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg$

6 0

2 years ago