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sergeinik [125]
3 years ago
7

The _______ is the layer of the atmosphere in which weather occurs

Physics
1 answer:
seraphim [82]3 years ago
8 0
The "Troposphere" <span>is the layer of the atmosphere in which weather occurs!

It is the lowermost layer of atmosphere, where we live.

Hope this helps!</span>
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Suppose a 20-foot ladder is leaning against a building, reaching to the bottom of a second-floor window 15 feet above the ground
Papessa [141]

Answer:

The answer is β=0,85 rads

Explanation:

As the ladder is leaning against the building, we can imagine there´s a triangle where 20ft is the hypotenuse and 15ft is the maximum vertical distance between the ladder and the ground, it means, the leg opposite to β which is the angle we need

Let β(betha) be the angle between the ladder and the ground

We also know that sin(betha)=(leg opposite)/(hypotenuse)

In this case we will need to find β, this way:

betha=sin^-1((15ft/20ft))

Then β=48,6°  

We also have that 2πrads is equal to 360°, in this way we find how much β is in radians:

betha=(48,6°)*(2pirads/360°)

then we find β=0,85rads

7 0
3 years ago
If the period of a wave is 0.05 s, then what is its frequency?
yKpoI14uk [10]
Frequency = 1/time period = 1/0.05 = 20s^-1. 
8 0
3 years ago
Read 2 more answers
The unit of length most suitable for measuring the thickness of a cell phone is a . The unit of length most suitable for measuri
ArbitrLikvidat [17]

The answers include the following:

  • The unit of length most suitable for measuring the thickness of a cell phone is a meter.
  • The unit of length most suitable for measuring the height of a backyard tree is a meter.

<h3>What is Meter?</h3>

This is defined as the standard unit for measuring the length of a body and is denoted as m.

Height is a vertical type of length which is why meter was chosen as the most appropriate choice.

Read more about Meter here brainly.com/question/1578784

#SPJ1

4 0
2 years ago
A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult
Dvinal [7]

Answer:

Explanation:

Given

time taken t=2\ s

Speed acquired in 2 sec v=42\ m/s

Here initial velocity is zero u=0

acceleration is the rate of change of velocity in a given time

a=\frac{v-u}{t}

a=\frac{42-0}{2}=21\ m/s^2

Distance travel in this time

s=ut+0.5at^2

where  

s=displacement

u=initial velocity

a=acceleration

t=time

s=0+\0.5\times 21\times (2)^2

s=42\ m

so Jet Plane travels a distance of 42 m in 2 s                                

5 0
3 years ago
When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt be
Veronika [31]
The problem seems to be incomplete because there is no question. However, from the problem description, the logical question is to find he acceleration needed by the jet to land on the airplane carrier. The working equation would be:

2ad = v₂² - v₁²
Since the jet stops, v₂ = 0. Substituting the values:
2(a)(95 m) = 0² - [(240 km/h)(1000 m/1 km)(1h/3600 s)]²
Solving for a,
<em>a = -23.39 m/s² (the negative sign indicates that the jet is decelerating)</em>
8 0
4 years ago
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