Question

A plane cruising at 233 m/s accelerates at 17 m/s 2 for 4.8 s. What is its final velocity? Answer in units of m/s. 013 (part 2 of 2) 10.0 points How far will it have traveled in that time? Answer in units of m.

Answer 1

Answer:

Final velocity will be 314.6 m/sec

Distance traveled = 1314.24 m

Explanation:

We have given initial velocity u = 233 m/sec

Acceleration $a=17m/sec^2$

Time t = 4.8 sec

From first equation of motion $v=u+at$, here v is final velocity, u is initial velocity and t is time

So $v=233+17\times 4.8=314.6m/sec$

Now we have to find distance traveled

From second equation of motion

$S=ut+\frac{1}{2}at^2=233\times 4.8+\frac{1}{2}\times 17\times 4.8^2=1314.24m$

So distance traveled in given time will be 1314.24 m