Answer:
Explanation:
If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.
In our case, we want to calculate the acceleration, so we write:
With the values we have we get:
Answer:
a) 12.0 m/s
b) 9.81 m/s in the downward direction
Explanation:
The initial velocity of the ball in the horizontal direction = 12.0 m/s
a) The velocity of the baseball in the x-direction remains the same therefore, we have;
The velocity of the ball in the x-direction (horizontal direction) after 1 second = 12.0 m/s because there is no net acceleration in the horizontal direction
b) The velocity in the y-direction is given by the following kinematic equation;
v = u - g × t
Where;
v = The final vertical velocity of the ball after t seconds
u = The initial vertical velocity = 0
g = The acceleration due to gravity = 9.81 m/s²
t = The time taken in motion = 1.00 s
Substituting the values gives;
v = 0 - 9.81 m/s² × 1.00 s = -9.81 m/s
v = -9.81 m/s
The vertical velocity of the ball after 1.00 second = -9.81 m/s which is 9.81 m/s downwards.
All of the following are examples of physical properties except tearing.
<h3>
What is Physical property?</h3>
This is used to describe the state of a physical system and is usually measurable.
Examples include:
Tearing isn't an example of a physical property which was why option A was chosen as the most appropriate choice.
Read more about Physical property here brainly.com/question/17436856
Answer:
5.843 m
Explanation:
suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.
lets consider that horizontal motion
distance = speed * time
time = 40/ 37 = 1.081 s
arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.
applying motion equation
(assume g = 10 m/s²)
Arrow misses the target by 5.843m ig the arrow us split horizontally
Period is T = 1/f. The frequency, f, is 5cycles/10s = 0.5. So the period T=1/0.2 = 2.