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Fudgin [204]
3 years ago
8

The sport with the fastest moving ball is jai alai, where measured speeds can be 286 km/h. If a professional jai alai player fac

es a ball at that speed and involuntarily blinks, he blacks out the scene for 100 ms. How far does the ball move during the blackout
Physics
1 answer:
cricket20 [7]3 years ago
5 0

Answer:

d= 794.4 cmExplanation:

Given that

Speed ,V= 286 km/h

=286\times \dfrac{1000}{3600}\ m/s

V=79.44 m/s

Given that time ,t= 100 ms

t= 0.1 s

We know that ( if acceleration is zero)

Distance = Speed x time

d= V t

Now by putting the values in the above equation

d = 79.44 x 0.1 m

d= 7.944 m

We know that 1 m = 100 cm

d= 794.4 cm

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Hi there!

1.

Hooke's law states that:

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Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.

2.

The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)

3.

The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.

4.

We can begin by looking at the given graph.

When the spring force = 4N, the total length of the spring is 35 cm.

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5.1.

If the spring elongates by 10 cm, the total length of the spring is:

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According to the graph, a length of 40 cm corresponds to a force of 8N.

5.2.

We can solve for the weight of the ball using the following:

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Using a summation of forces:

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The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:

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5.3.

0 = T - Mg

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Use the prior value of T and gravity to solve:

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