An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg of sodium phenate. What is the ph of the solution. The pka of phenol = 9.98. Mw of phenol and sodium phenate are 94 g/mol and 116 g/mol, respectively.
Volume of solution = 55 gallons = 208.2 L [ 1 gallon = 3.78 L]
moles of phenol = mass / molar mass = 4000 g / 94 = 42.55 moles
moles of sodium phenate = mass / molar mass = 1500 / 116 = 12.93 moles
pKa of phenol = 9.98
We know that the pH of buffer is calculated using Hendersen Hassalbalch's equation
pH = pKa + log [salt] / [acid]
volume is same for both the sodium phenate and phenol has we can directly take the moles of each in the formula
pH = 9.98 + log [12.93 / 42.55] = 9.46
Answer:
0.3477 grams
The conversion factor is 1/1000
Explanation:
347.7 mg = 0.3477 grams
1 mg = 1x10⁻³ g
1 g / 1000 mg . 347.7 mg = 0.3477 grams
<h3><u>Answer;</u></h3>
0.002512 moles of H2O
<h3><u>Explanation</u>;</h3>
The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;
CH3COOH + NaOH ------> CH3COONa + H2O
Number of moles of CH3COOH = molarity × volume in litres
= 0.08 × 31.4/1000
= 2.512 × 10^-3
Similarly number of moles of NaOH = 1 × 24.3/1000
= 0.0243
From the reaction the mole ratio of CH3COOH : NaOH
Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512 moles, which is less than what is required.
Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.
Since; 1 mole of CH3COOH gives 1 mole of water.
Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O
Answer:
17.92L or 17.92dm³1
Explanation:
number of moles of a gas = volume of that gas/ 22.4(S.V.P)
0.8 mol = x / 22.4
cross multiplication
x = 22.4 × 0.8
x = 17.92
:. the volume of 0.8 mol of nitrogen gas is 17.92dm³ or 17.92L
The mass of Ca(CN)2 : 92,11 g/mol
<h3>Further explanation</h3>
Given
0.0321 moles of Ca(CN)2
Required
The mass
Solution
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
mol(n) = mass(m) : MW(molecular weight)
Input the value :
mass = mol x MW Ca (CN)2
mass = 0.0321 x 92,11 g/mol
mass = 2.957 g