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Stels [109]
3 years ago
9

How many moles of water are produced when 24.3 ml of 0.100 m naoh is mixed with 31.4 ml of 0.08 m acetic acid?

Chemistry
1 answer:
slega [8]3 years ago
5 0
<h3><u>Answer;</u></h3>

0.002512 moles of H2O

<h3><u>Explanation</u>;</h3>

The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;

CH3COOH + NaOH ------> CH3COONa + H2O

Number of moles of CH3COOH = molarity × volume in litres

                                                     = 0.08 × 31.4/1000

                                                     = 2.512 × 10^-3  

Similarly number of moles of NaOH = 1 × 24.3/1000

                                                      = 0.0243

From the reaction the mole ratio of CH3COOH : NaOH

Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512  moles, which is less than what is required.

Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.

Since; 1 mole of CH3COOH gives 1 mole of water.

Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O

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3 years ago
Name the following alkyne.<br> Please help me &lt;3
Alexandra [31]

Answer:

D. 7-methyl-3-octyne

Explanation:

1) Identify the parent chain and name it like an alkane.

• The longest chain of carbons, which consists of the functional group (which is the alkyne group in this case: C≡C).

• There are 8 carbons in the longest chain, so it is called an octane.

2) Now, identify the location of the functional group.

• The location number of the functional group should be as low as possible. Thus although we could count from the right, we start counting from the left since the functional group is closer to the left. From the left, the functional group would be at carbon 8 while from the left, it is on carbon 3.

• Replace 'ane' with 'yne' in octane for the alkyne group.

• This would give us 3-octyne.

3) Lastly, add in the name of the branch.

• Here we have one branch, -CH₃. This is read as methyl.

• Identify the location number of the branch by counting the number of carbons in the same direction as when we counted the location number of the functional group. The methyl branch has a location number of 7.

• Adding the name of the branch before the parent chain, we would arrive at 7-methyl-3-octyne as the IUPAC name of the alkyne.

Further Explanation:

A) This option is incorrect as there are only 8 carbons in the parent chain. Although there are 9 carbons in total, the 9th carbon is taken care of in '7-methyl'.

B) Location number of the functional group should be as low as possible, so start counting the number of carbons from the left!

C) Since the functional group is an alkyne, the word 'octane' should be 'octyne' instead.

8 0
3 years ago
A brine is used to measure the absolute permeability of a core plug. The rock sample is 4 cm long and 3 cm 2 in cross section. T
nydimaria [60]

Answer : The absolute permeability is, 0.111 darcys.

Explanation : Given,

Volumetric constant rate = 0.5cm^3/s

Cross section area = 3cm^2

Pressure = 2 atm

Viscosity = 1.0 cp

Length of rock = 4 cm

From the Darcy equation  we conclude that,

\text{Volumetric constant rate}=\frac{(\text{Absolute permeability}\times A\times P)}{\eta \times l}

where,

A = cross section area

P = pressure

\eta = viscosity

l = length of rock

Now put all the given values in the above formula, we get:

0.5cm^3/s=\frac{(\text{Absolute permeability}\times 3cm^2\times 2\text{ atm})}{1.0cp \times 4cm}

\text{Absolute permeability}=0.111\text{ darcys}

Therefore, the absolute permeability is, 0.111 darcys.

8 0
3 years ago
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