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melomori [17]
3 years ago
14

[HCN]=0.09974 M Kp=7.52 Calculate the partial pressure of HCN ?

Chemistry
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

i don't understand

Explanation:

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A) 30.22 g NaCl x 1 mol NaC l =      58.4430 Molar mass (g) NaCl=0.5171 mol NaCl
jekas [21]
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.

So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl. 
6 0
3 years ago
When road contractors are laying cement,they first place a series of steel rods in a specific patterns. the they pour the cement
Anna11 [10]
The steel rods will enable the concrete to form without any bumps and it will add shape to the cement and strength, so no odd massive lumps are formed.

That is what I think anyways :)
3 0
2 years ago
Read 2 more answers
Help asap plz!!
musickatia [10]

Answer:

Large change in temperature makes heat flow fast.

Explanation:

3 0
3 years ago
A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

3 0
3 years ago
Help please ASAP just with number 9
Crank
I don’t know I just need to ask a question
5 0
3 years ago
Read 2 more answers
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